org.hibernate.tool.schema.spi.CommandAcceptanceExc

问题:

While running spring boot with h2 database and JPA i am getting below error.

org.hibernate.tool.schema.spi.CommandAcceptanceException: Error executing DDL via JDBC Statement
    at org.hibernate.tool.schema.internal.exec.GenerationTargetToDatabase.accept(GenerationTargetToDatabase.java:67) ~[hibernate-core-5.2.17.Final.jar:5.2.17.Final]
    at org.hibernate.tool.schema.internal.SchemaCreatorImpl.applySqlString(SchemaCreatorImpl.java:440) [hibernate-core-5.2.17.Final.jar:5.2.17.Final]

It is caused due to below one

Caused by: org.h2.jdbc.JdbcSQLException: Syntax error in SQL statement "CREATE TABLE EXCHANGE_VALUE (ID INTEGER NOT NULL, CONVERSION_MULTIPLE DECIMAL(19,2), FROM[*] VARCHAR(255), PORT INTEGER NOT NULL, TO VARCHAR(255), PRIMARY KEY (ID)) "; expected "identifier"; SQL statement:
create table exchange_value (id integer not null, conversion_multiple decimal(19,2), from varchar(255), port integer not null, to varchar(255), primary key (id)) [42001-197]
    at org.h2.message.DbException.getJdbcSQLException(DbException.java:357) ~[h2-1.4.197.jar:1.4.197]
    at org.h2.message.DbException.getSyntaxError(DbException.java:217) ~[h2-1.4.197.jar:1.4.197]

My hibernate class

import java.math.BigDecimal;

import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.Table;

@Entity
@Table(name="Exchange_Value")
public class ExchangeValue {

    @Id
    @GeneratedValue(strategy=GenerationType.AUTO)
    private int id; 
    private String from;
    private String to;
    private BigDecimal conversionMultiple;
    private int port;

    public ExchangeValue() {

    }

    public ExchangeValue(String from, String to, BigDecimal conversionMultiple) {
        super();
//      this.id = id;
        this.from = from;
        this.to = to;
        this.conversionMultiple = conversionMultiple;
    }
    public int getId() {
        return id;
    }
    public void setId(int id) {
        this.id = id;
    }   
}

application.properties is below

spring.application.name=currency-exchange-service
server.port=8000
spring.jpa.hibernate.ddl-auto= create-drop

Just want to know as to what i am missing in the code tried adding spring.jpa.hibernate.ddl-auto= create-drop but it did not helped.

回答1:

@shubh.. Your Entity Field names are matching with SQL reserved keywords,

So try to change the field names otherwise use name attribute with @Column Annotation (which gives alias names to the DATABASE)

    @Column(name="valueFrom") 
    private String from;

    @Column(name="valueTo") 
    private String to;

    private BigDecimal conversionMultiple;
    private int port;

回答2:

Your Entity Field name from was matched with database reserved word from, change the field name to another, or add a @Column annotation on that field. Like:

...

@Column(name = "_from")
private String from;

...

回答3:

I faced the same issue. I did the mistake in giving the schema name in mysql database.

In spring.properties -> (spring boot application)
spring.datasource.url=jdbc:mysql://localhost:3306/db_microservice

Here instead of "db_microservice" I Have given the name as "db-microservice". So don't use "-". And this solved my issue.

回答4:

@ganesh045's response isnt actually true because hibernate's table creation query works like this: CREATE TABLE <your_table> 'password' for example to each of your attributes. Adding the `` to the attribute will make SQL read it NOT as reserved keyword. It also does the same when it queries for your select clauses inside JpaRepository. It will make a call such as this: SELECT 'attribute' FROM <your_table>. Your problem is most likely that you specified your schema name as kebab-case or anything which is not camelCase and snake_case. Also, with this approach you can have a table called User with attribute's username and password which actually also are MYSQL reserved keywords.