The following snippet draws a gray square.
glColor3b(50, 50, 50);
glBegin(GL_QUADS);
glVertex3f(-1.0, +1.0, 0.0); // top left
glVertex3f(-1.0, -1.0, 0.0); // bottom left
glVertex3f(+1.0, -1.0, 0.0); // bottom right
glVertex3f(+1.0, +1.0, 0.0); // top right
glEnd();
In my application, behind this single square exists a colored cube.
What function should I use to make square (and only this square) opaque?
In the init function, use these two lines:
glEnable(GL_BLEND);
glBlendFunc(GL_SRC_ALPHA, GL_ONE_MINUS_SRC_ALPHA);
And in your render function, ensure that glColor4f
is used instead of glColor3f
, and set the 4th argument to the level of opacity required.
glColor4f(1.0, 1.0, 1.0, 0.5);
glBegin(GL_QUADS);
glVertex3f(-1.0, +1.0, 0.0); // top left
glVertex3f(-1.0, -1.0, 0.0); // bottom left
glVertex3f(+1.0, -1.0, 0.0); // bottom right
glVertex3f(+1.0, +1.0, 0.0); // top right
glEnd();
glColor4f(float r,float g, float b, flaot alpha);
(in your case maybe clColor4b)
also make sure, that blending is enabled.
(you have to reset the color to non-alpha afterwads, which might involve a glGet* to save the old vertexcolor)
Use glColor4
instead of glColor3
. For example:
glBlendFunc(GL_SRC_ALPHA,GL_ONE);
glColor4f(1.0f,1.0f,1.0f,0.5f);
You can set colors per vertex
glBegin(GL_QUADS);
glColor4f(1.0, 0.0, 0.0, 0.5); // red, 50% alpha
glVertex3f(-1.0, +1.0, 0.0); // top left
// Make sure to set the color back since the color state persists
glVertex3f(-1.0, -1.0, 0.0); // bottom left
glVertex3f(+1.0, -1.0, 0.0); // bottom right
glVertex3f(+1.0, +1.0, 0.0); // top right
glEnd();