How to sort an array of objects with jquery or jav

2018-12-31 19:09发布

问题:

This question already has an answer here:

  • Sorting an array of JavaScript objects 25 answers

I have an array of objects:

var array = [(id, name, value),(id, name, value)]; //and so on

How do I get the array to be sorted in ascending order of the atribute name (array[i][1])?

I\'ve tried to do this: array[i][1].sort(), but that doesn\'t work.

Please help me!

Edit: the array can contain more than two objects! It can contain hundreds.

Edit: Why is this question marked as a duplicate, when it was asked 2 years before the \"duplicated\" question?

回答1:

//This will sort your array
function SortByName(a, b){
  var aName = a.name.toLowerCase();
  var bName = b.name.toLowerCase(); 
  return ((aName < bName) ? -1 : ((aName > bName) ? 1 : 0));
}

array.sort(SortByName);


回答2:

var array = [[1, \"grape\", 42], [2, \"fruit\", 9]];

array.sort(function(a, b)
{
    // a and b will here be two objects from the array
    // thus a[1] and b[1] will equal the names

    // if they are equal, return 0 (no sorting)
    if (a[1] == b[1]) { return 0; }
    if (a[1] > b[1])
    {
        // if a should come after b, return 1
        return 1;
    }
    else
    {
        // if b should come after a, return -1
        return -1;
    }
});

The sort function takes an additional argument, a function that takes two arguments. This function should return -1, 0 or 1 depending on which of the two arguments should come first in the sorting. More info.

I also fixed a syntax error in your multidimensional array.



回答3:

//objects
var array = [{id:\'12\', name:\'Smith\', value:1},{id:\'13\', name:\'Jones\', value:2}];
array.sort(function(a, b){
    var a1= a.name.toLower(), b1= b.name.toLower();
    if(a1== b1) return 0;
    return a1> b1? 1: -1;
});

//arrays
var array =[ [\'12\', ,\'Smith\',1],[\'13\', \'Jones\',2]];
array.sort(function(a, b){
    var a1= a[1], b1= b[1];
    if(a1== b1) return 0;
    return a1> b1? 1: -1;
});


回答4:

data.sort(function(a,b) 
{
   return a.val - b.val;
});


回答5:

the sort method contains an optional argument to pass a custom compare function.

Assuming you wanted an array of arrays:

var arr = [[3, \"Mike\", 20],[5, \"Alex\", 15]];

function compareName(a, b)
{

  if (a[1] < b[1]) return -1;
  if (a[1] > b[1]) return 1;
  return 0;
}
arr.sort(compareName);

Otherwise if you wanted an array of objects, you could do:

function compareName(a, b)
{

  if (a.name < b.name) return -1;
  if (a.name > b.name) return 1;
  return 0;
}


回答6:

Well, it appears that instead of creating a true multidimensional array, you\'ve created an array of (almost) JavaScript Objects. Try defining your arrays like this ->

var array = [ [id,name,value], [id,name,value] ]

Hopefully that helps!