I want to remove (uncommnet #) wheel group in /etc/sudoers file so what would be the Regex pattern i should use?
#cat /etc/sudoers
....
....
## Allows members of the 'sys' group to run networking, software,
## service management apps and more.
# %sys ALL = NETWORKING, SOFTWARE, SERVICES, STORAGE, DELEGATING, PROCESSES, LOCATE, DRIVERS
## Allows people in group wheel to run all commands
# %wheel ALL=(ALL) ALL
## Same thing without a password
# %wheel ALL=(ALL) NOPASSWD: ALL
....
....
I want to remove # from following line.
...
# %wheel ALL=(ALL) NOPASSWD: ALL
...
You shouldn't edit the /etc/sudoers
file with any sort of script. There's a reason for the visudo
command. Edits to the sudoers
file should be rare and well-controlled.
That being said, if your editor for the visudo
command is vi, you can run something like :%s/^# %wheel/%wheel/
to uncomment all of the lines what start with %wheel
.
Or, if you reeeeeeally think it's necessary:
sudo sed --in-place 's/^#\s*\(%wheel\s\+ALL=(ALL)\s\+NOPASSWD:\s\+ALL\)/\1/' /etc/sudoers
Run it without the --in-place
first to check the output. Use it at your own risk.
No need to use sed. On centos you can simply create file at /etc/sudoers.d/
echo 'myuser ALL=(ALL) NOPASSWD: ALL' >> ./myuser
sudo chown root:root ./myuser
sudo mv ./myuser /etc/sudoers.d/
This will enable sudo without password for myuser
. Check this for more information: https://unix.stackexchange.com/questions/375433/etc-sudoers-vs-etc-sudoers-d-file-for-enabling-sudo-for-a-user
The following should work:
sed -i 's/^#\s*\(%wheel\s*ALL=(ALL)\s*NOPASSWD:\s*ALL\)/\1/' /etc/sudoers