问题:

For example,

A = [ -1   0  -2   0   0
   2   8   0   1   0
   0   0   3   0  -2
   0  -3   2   0   0
   1   2   0   0  -4];

how can I get a vector of the first nonzero elements of each row?

回答1:

You can use max:

>> [sel, c] = max( A ~=0, [], 2 );

Rows for which sel equalse zero - are all zeros and the corresponding column in c should be ignored.

Result:

>> [sel c]= max( A~=0, [], 2 )

sel =
 1
 1
 1
 1
 1
c =
 1
 1
 3
 2
 1

In order to find the first non-zero row index (for each column) you just need to apply max on the first dimension:

>> [sel r] = max( A~=0, [], 1 );

回答2:

Here is a solution based on accumarray that will work even if a row is all zeros.

A = [ -1   0  -2   0   0
   2   8   0   1   0
   0   0   3   0  -2
   0  -3   2   0   0
   1   2   0   0  -4];

[r,c] = find(A);

%# for every row, take the minimum column index and put NaN if none is found
firstIndex = accumarray(r,c,[size(A,1),1],@min,NaN);

回答3:

You can do it by executing find function for each row as follows:

A = [ -1   0  -2   0   0
   2   8   0   1   0
   0   0   3   0  -2
   0  -3   2   0   0
   1   2   0   0  -4];

% make cell of rows
cellOfRows = num2cell(A, 2);

% apply find function for each row
indexOfFirstNonZeroValues = cellfun(@(row) find(row, 1, 'first'), cellOfRows);


indexOfFirstNonZeroValues =

     1
     1
     3
     2
     1