I need install this specific version (7.19.0) pycurl.
When I try to install with this command:
pip install pycurl==7.19.0
I'm receiving this error.
Failed building wheel for pycurl Running setup.py clean for pycurl Failed to build pycurl Installing collected packages: pycurl
..... // MULTIPLE LINES
build/temp.linux-x86_64-2.7/src/pycurl.o: na função `initpycurl':
/tmp/pip-build-4Q4V7Q/pycurl/src/pycurl.c:3904: referência indefinida para `PyEval_InitThreads'
collect2: error: ld returned 1 exit status
error: command 'x86_64-linux-gnu-gcc' failed with exit status 1
---------------------------------------- Command "/home/user/.virtualenvs/myenv/bin/python2 -u -c "import setuptools, tokenize;__file__='/tmp/pip-build-4Q4V7Q/pycurl/setup.py';exec(compile(getattr(tokenize, 'open', open)(__file__).read().replace('\r\n', '\n'), __file__, 'exec'))" install --record /tmp/pip-UlYKto-record/install-record.txt --single-version-externally-managed --compile --install-headers /home/user/.virtualenvs/myenv/include/site/python2.7/pycurl" failed with error code 1 in /tmp/pip-build-4Q4V7Q/pycurl/
How can I do to install this specific version?
I'm using Ubuntu 16.
Thanks!