Say we have the following classes and some values (in Scala):
class A[T](val x: T)
class B[T](x: T, val y: T) extends A[T](x)
val x1 = new A("test")
val x2 = new B(1,2)
val x3 = new B("foo","bar")
val x4 = new A(1)
Further, we define the following polymorphic function value (using shapeless):
object f extends (A ~> Option) {
def apply[T](s: A[T]) = Some(s.x)
}
Now we can call:
f(x1); f(x2); f(x3); f(x4)
Which all succeed (and should IMHO). However:
val list = x1 :: x2 :: x3 :: x4 :: HNil
list.map(f)
// could not find implicit value for parameter mapper:
// shapeless.Mapper[f.type,shapeless.::[A[String],shapeless.::[
// B[Int],shapeless.::[B[String],shapeless.::[A[Int],shapeless.HNil]]]]]
Where I was expecting:
Some("test") :: Some(1) :: Some("foo") :: Some(1) :: HNil
Note that this works:
val list2 = x1 :: x4 :: HNil // only instances of A
list2.map(f)
UPDATE
It seems that if we specify each case separately, it's fine:
object f extends Poly1 {
implicit def caseA[T] = at[A[T]]{s => Some(s.x)}
implicit def caseB[T] = at[B[T]]{s => Some(s.x)}
}
However, trying to express this a bit smarter, does not work (not even for simple applications):
object f extends Poly1 {
implicit def caseA[T, S <: A[T]] = at[S]{s => Some(s.x)}
}