I am compiling my code using following command:
gcc -O3 -ftree-vectorizer-verbose=6 -msse4.1 -ffast-math
With this all the optimizations are enabled.
But I want to disable vectorization while keeping the other optimizations.
I am compiling my code using following command:
gcc -O3 -ftree-vectorizer-verbose=6 -msse4.1 -ffast-math
With this all the optimizations are enabled.
But I want to disable vectorization while keeping the other optimizations.
Most of the GCC switches can be used with a no
prefix to disable their behavior. Try with -fno-tree-vectorize
(after -O3
on the command line).
you can also selectively enable and disable vectorization with the optimize function attributes or pragmas
http://gcc.gnu.org/onlinedocs/gcc/Function-Attributes.html
http://gcc.gnu.org/onlinedocs/gcc/Function-Specific-Option-Pragmas.html
e.g.
__attribute__((optimize("no-tree-vectorize")))
void f(double * restrict a, double * restrict b)
{
for (int i = 0; i < 256; i++)
a[i] += b[i];
}
Excellent, now that gcc has become more aggressive at vectorizing e.g.
extern "C" __attribute__((optimize("no-tree-vectorize")))
/* Subroutine */
int s111_ (integer * ntimes, integer * ld, integer * n,
real * ctime, real * dtime,
real * __restrict a, real * b, real * c__, real * d__,
real * e, real * aa, real * bb, real * cc)
{
....
for (i__ = 2; i__ <= i__2; i__ += 2)
a[i__] = a[i__ - 1] + b[i__];
....
In the case posted above, removing restrict
used to do the job, but now g++ 6.0 can't be stopped from vectorizing by removing __restrict
.