PHP Zend date format

问题:

I want to input a timestamp in below format to the database.

yyyy-mm-dd hh:mm:ss

How can I get in above format?

When I use

$date = new Zend_Date();

it returns month dd, yyyy hh:mm:ss PM

I also use a JavaScript calender to insert a selected date and it returns in dd-mm-yyyy format

Now, I want to convert these both format into yyyy-mm-dd hh:mm:ss so can be inserted in database. Because date format not matching the database field format the date is not inserted and only filled with *00-00-00 00:00:00*

Thanks for answer

回答1:

Not sure if this will help you, but try using:

 // to show both date and time,
 $date->get('YYYY-MM-dd HH:mm:ss');

 // or, to show date only
 $date->get('YYYY-MM-dd') 

回答2:

Technically, @stefgosselin gave the correct answer for Zend_Date, but Zend_Date is completely overkill for just getting the current time in a common format. Zend_Date is incredibly slow and cumbersome to use compared to PHP's native date related extensions. If you don't need translation or localisation in your Zend_Date output (and you apparently dont), stay away from it.

Use PHP's native date function for that, e.g.

echo date('Y-m-d H:i:s');

or DateTime procedural API

echo date_format(date_create(), 'Y-m-d H:i:s');

or DateTime Object API

$dateTime = new DateTime;
echo $dateTime->format('Y-m-d H:i:s');

Don't do the common mistake of using each and every component Zend Frameworks offers just because it offers it. There is absolutely no need to do that and in fact, if you can use a native PHP extension to achieve the same result with less or comparable effort, you are better off with the native solution.

Also, if you are going to save a date in your database, did you use any of the DateTime related columns in your database? Assuming you are using MySql, you could use a Timestamp column or an ISO8601 Date column.

回答3:

This is how i did it:

abstract class App_Model_ModelAbstract extends Zend_Db_Table_Abstract
{

    const DATE_FORMAT = 'yyyy-MM-dd';

    public static function formatDate($date, $format = App_Model_ModelAbstract::DATE_FORMAT)
    {
        if (!$date instanceof Zend_Date && Zend_Date::isDate($date)) {
            $date = new Zend_Date($date);
        }

        if ($date instanceof Zend_Date) {
            return $date->get($format);
        }

        return $date;
    }
}

this way you don't need to be concerned with whether or not its actually an instance of zend date, you can pass in a string or anything else that is a date.

回答4:

a simple way to use Zend Date is to make specific function in its business objects that allows to parameter this function the date format. You can find a good example to this address http://www.pylejeune.fr/framework/utiliser-les-date-avec-zend_date/

回答5:

this is i did it :
Zend_Date::now->toString('dd-MM-yyyy HH:mm:ss')
output from this format is "24-03-2012 13:02:01"
and you can modified your date format

回答6:

I've always use $date->__toString('YYYY-MM-dd HH-mm-ss'); method in the past but today didn't work. I was getting the default output of 'Nov 1, 2013 12:19:23 PM'

So today I used $date->get('YYYY-MM-dd HH-mm-ss'); as mentioned above. Seems to have solved my problem.

You can find more information on this on output formats here: http://framework.zend.com/manual/1.12/en/zend.date.constants.html