How to let jackson generate json string using sing

2020-07-02 10:39发布

问题:

For example, I want to generate a json string for ng-style:

<th ng-style="{width:247}" data-field="code">Code</th>

But with jackson, the result is:

<th ng-style="{&quot;width&quot;:247}" data-field="code">Code</th>

It's not easy to read.

So I want jackson to generate the json string with single quote or no quotes. Is it possible to do this?

回答1:

If you have control over the ObjectMapper instance, then configure it to handle and generate JSON the way you want:

final ObjectMapper mapper = new ObjectMapper();
mapper.configure(JsonGenerator.Feature.QUOTE_FIELD_NAMES, false);
mapper.configure(JsonParser.Feature.ALLOW_UNQUOTED_FIELD_NAMES, true);


回答2:

The simplest and the best option is to use regular expression and update the string value.

The sample code is as listed below.

partNumberList=partNumberList.replaceAll(":", ":\"").replaceAll("}", "\"}");

The complete code is as shown below

public static void main(String[] args) throws JsonParseException, JsonMappingException, 
    IOException {
    TestJack obj = new TestJack();
    //var jsonString ='{"it":"Stati Uniti d'America"}';
    //            jsonString =jsonString.replace("'", "\\\\u0027")
    ObjectMapper mapper = new ObjectMapper();
    String partNumberList = "[{productId:AS101R}, {productId:09902007}, {productId:09902002}, {productId:09902005}]";
    partNumberList = partNumberList.replaceAll(":", ":\"").replaceAll("}", "\"}");
    System.out.println(partNumberList);
    mapper.configure(com.fasterxml.jackson.core.JsonParser.Feature.ALLOW_UNQUOTED_FIELD_NAMES, true);
    List<ProductDto> jsonToPersonList = null;
    jsonToPersonList = mapper.readValue(partNumberList, new TypeReference<List<ProductDto>>() {
    });
    System.out.println(jsonToPersonList);
}