How do I give an array an attribute during seriali

问题:

I'm trying to generate C# that creates a fragment of XML like this.

<device_list type="list">
    <item type="MAC">11:22:33:44:55:66:77:88</item>
    <item type="MAC">11:22:33:44:55:66:77:89</item>
    <item type="MAC">11:22:33:44:55:66:77:8A</item>
</device_list>

I was thinking of using something like this:

[XmlArray( "device_list" ), XmlArrayItem("item")]
public ListItem[] device_list { get; set; }

as the property, with this class declaration:

public class ListItem {
    [XmlAttribute]
    public string type { get; set; }

    [XmlText]
    public string Value { get; set; }
}

Which gives me the inner serialization, but I don't know how to apply the type="list" attribute to the device_list above.

I'm thinking (but not sure of how to write the syntax) that I need to do a:

public class DeviceList {
    [XmlAttribute]
    public string type { get; set; }

    [XmlArray]
    public ListItem[] .... This is where I get lost
}

Updated based on Dave's responses

public class DeviceList : List<ListItem> {
    [XmlAttribute]
    public string type { get; set; }
}

public class ListItem {
    [XmlAttribute]
    public string type { get; set; }

    [XmlText]
    public string Value { get; set; }
}

and the usage is currently:

[XmlArray( "device_list" ), XmlArrayItem("item")]
public DeviceList device_list { get; set; }

And the type, while being declared in the code like thus:

device_list = new DeviceList{type = "list"}
device_list.Add( new ListItem { type = "MAC", Value = "1234566" } );
device_list.Add( new ListItem { type = "MAC", Value = "1234566" } );

Isn't showing the type on serialization. This is the result of the serialization:

<device_list>
  <item type="MAC">1234566</item>
  <item type="MAC">1234566</item>
</device_list>

So apparently I'm still missing something...

回答1:

Using part of Dave's answer above, I found that it was best to use the property in the declaring class like this: (note the lack of attributes)

public DeviceList device_list { get; set; }

and then update the DeviceList class like this:

[XmlType("device_list")]
[Serializable]
public class DeviceList {
    [XmlAttribute]
    public string type { get; set; }

    [XmlElement( "item" )]
    public ListItem[] items { get; set; }
}

and keep the original ListItem class

public class ListItem {
    [XmlAttribute]
    public string type { get; set; }

    [XmlText]
    public string Value { get; set; }
}

and my serialization is as expected:

<device_list type="list">
  <item type="MAC">1234567</item>
  <item type="MAC">123456890</item>
</device_list>

回答2:

Instead of using a ListItem[], derive a new class from List<T> called DeviceList:

public class DeviceList : List<ListItem>
{
   [XmlElement(ElementName = "type")]
   public string ListType {get;set;}

}

Then, in a containing class use that class to serialize the XML. The type value can be included as an element of the parent node, depending on the way you configure the serialization. I don't remember the exact syntax, but I think class properties are added as node elements by default.

Containing class:

public class SerializeMyStuff
{
   public SeriazlieMyStuff()
   {
       ListOfDevices = new DeviceList();
       ListOfDevices.ListType = "list";
   }

   [XmlArray( "device_list" ), XmlArrayItem("item")]
   public DeviceList ListOfDevices {get;set;}
}

回答3:

You could also achieve the desired behaviour by implementing [IXmlSerializable][1] in your container class:

With the below code I get the following markup:

<?xml version="1.0"?>
<DeviceList type="list">
  <Item xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" type="MAC">11:22:33:44:55:66:77:88</Item>
  <Item xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" type="MAC">11:22:33:44:55:66:77:89</Item>
  <Item xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" type="MAC">11:22:33:44:55:66:77:8A</Item>
</DeviceList>

code:

public class Item
{
    [XmlAttribute("type")]
    public string Type { get; set; }

    [XmlText]
    public string Value { get; set; }
}

public class DeviceList : IXmlSerializable
{
    public string Type { get; set; }

    public List<Item> Items { get; set; } 


    public System.Xml.Schema.XmlSchema GetSchema()
    {
        return null;
    }

    public void ReadXml(System.Xml.XmlReader reader)
    {
        reader.MoveToContent();
    }

    public void WriteXml(System.Xml.XmlWriter writer)
    {
        writer.WriteAttributeString("type", Type);


        XmlSerializer serializer = new XmlSerializer(typeof(Item));
        foreach (var item in Items)
        {
            serializer.Serialize(writer, item);
        }
    }
}

I use the following code in my main method:

var dlist = new DeviceList
                {
                    Type = "list",
                    Items = new List<Item>
                                {
                                    new Item {Type = "MAC", Value = "11:22:33:44:55:66:77:88"},
                                    new Item {Type = "MAC", Value = "11:22:33:44:55:66:77:89"},
                                    new Item {Type = "MAC", Value = "11:22:33:44:55:66:77:8A"},
                                }
                };


using(FileStream stream = new FileStream(@"D:\jcoletest.xml", FileMode.Create, FileAccess.Write))
{
    new XmlSerializer(typeof (DeviceList)).Serialize(stream, dlist);
}

For more information look at this tutorial here