WPF Toggle Button Checked/Uchecked event with one

问题:

I am using a ToggleButton in a WPF window:

 <ToggleButton Height="37"
          HorizontalAlignment="Left"
          Margin="485.738,254.419,0,0"
          VerticalAlignment="Top"
          Width="109"
          IsEnabled="True"
          Checked="toggleAPDTimeoutErr_Checked"
          Unchecked="toggleAPDTimeoutErr_Unchecked">Timeout</ToggleButton>

I have two events that I am monitoring, but this is done in two different code behind handlers. How can this be done in only one?

I will have many ToggleButtons, and the code can get large.

回答1:

You can attach a single click event of your ToggleButton and in its handler you can check the ToggleButton IsChecked property by type casting the sender object in your handler like this -

private void ToggleButton_Click(object sender, RoutedEventArgs e)
{
   if((sender as ToggleButton).IsChecked)
   {
      // Code for Checked state
   }
   else
   {
      // Code for Un-Checked state
   }
}

Xaml:

<ToggleButton Height="37" HorizontalAlignment="Left" Margin="485.738,254.419,0,0"     VerticalAlignment="Top" Width="109" IsEnabled="True" Click="ToggleButton_Click">Timeout</ToggleButton>

回答2:

You should not use Click event as some answers suggest, because it will not work when the property IsChecked is changed by code or any other event than mouse (keyboard, animation..). This is simply a bug.

Instead you can use the same handler for both Checked and Unchecked and do action depending on IsChecked property.

<ToggleButton
    Checked="toggleButton_IsCheckedChanged"
    Unchecked="toggleButton_IsCheckedChanged" />

回答3:

Try this

private void tBtn_super_Click(object sender, RoutedEventArgs e)
        {
            if (tBtn_super.IsChecked == true)
            {
                MessageBox.Show("True");
            }
            else
            {
                MessageBox.Show("False");
            }
        }