I'm working on one GUI program, and was gonna add a long running task into one event, but I found this would make the whole program freeze a lot, so considering other people's advice I would make the GUI only responsible for starting, stopping and monitoring and make the long running task run as a separate script. The only way I know to run another script in one script is by import, is there any other methods to communicate with another script, I mean such as reading another's stdout and terminating it at any time you want?
问题:
回答1:
I suggest you look at the threading module. By subclassing the Thread
class you can create new threads for time intensive jobs.
Then for communication between the the threads you can use either pubsub or pydispatcher, I haven't tried the latter so I can't comment on it but I would recommend pubsub for its ease of use and the fact that its apart of wxpython is a bonus.
Here is a wxpython wiki page on running long tasks, skip to the end if you want the simplest example usage of threading.
Heres a simple (runnable) example of how you could use pubsub
to send messages from your workerThread to your GUI
.
import time
import wx
from threading import Thread
from wx.lib.pubsub import Publisher
class WorkerThread(Thread):
def __init__(self):
Thread.__init__(self)
#A flag that can be set
#to tell the thread to end
self.stop_flag = False
#This calls the run() to start the new thread
self.start()
def run(self):
""" Over-rides the super-classes run()"""
#Put everything in here that
#you want to run in your new thread
#e.g...
for x in range(20):
if self.stop_flag:
break
time.sleep(1)
#Broadcast a message to who ever's listening
Publisher.sendMessage("your_topic_name", x)
Publisher.sendMessage("your_topic_name", "finished")
def stop(self):
"""
Call this method to tell the thread to stop
"""
self.stop_flag = True
class GUI(wx.Frame):
def __init__(self, parent, id=-1,title=""):
wx.Frame.__init__(self, parent, id, title, size=(140,180))
self.SetMinSize((140,180))
panel = wx.Panel(id=wx.ID_ANY, name=u'mainPanel', parent=self)
#Subscribe to messages from the workerThread
Publisher().subscribe(self.your_message_handler, "your_topic_name")
#A button to start the workerThread
self.startButton = wx.Button(panel, wx.ID_ANY, 'Start thread')
self.Bind(wx.EVT_BUTTON, self.onStart, self.startButton)
#A button to stop the workerThread
self.stopButton = wx.Button(panel, wx.ID_ANY, 'Stop thread')
self.Bind(wx.EVT_BUTTON, self.onStop, self.stopButton)
#A text control to display messages from the worker thread
self.threadMessage = wx.TextCtrl(panel, wx.ID_ANY, '', size=(75, 20))
#Do the layout
sizer = wx.BoxSizer(wx.VERTICAL)
sizer.Add(self.startButton, 0, wx.ALL, 10)
sizer.Add(self.stopButton, 0, wx.ALL, 10)
sizer.Add(self.threadMessage, 0, wx.ALL, 10)
panel.SetSizerAndFit(sizer)
def onStart(self, event):
#Start the worker thread
self.worker = WorkerThread()
#Disable any widgets which could affect your thread
self.startButton.Disable()
def onStop(self, message):
self.worker.stop()
def your_message_handler(self, message):
message_data = message.data
if message_data == 'finished':
self.startButton.Enable()
self.threadMessage.SetLabel(str(message_data))
else:
self.threadMessage.SetLabel(str(message_data))
if __name__ == "__main__":
app = wx.PySimpleApp()
frame = GUI(None, wx.ID_ANY, 'Threading Example')
frame.Show()
app.MainLoop()
回答2:
If communicating by stdin/stdout is what you need, you should use the subprocess
module.
回答3:
There is much better way to do that, than reading stdout: http://docs.python.org/library/multiprocessing.html