get number of columns of a particular row in given

问题:

I want the number of columns of a particular row in excel. How is that possible? I used POI API

but I could get only columns count to 7 .

    try
            {
                fileInputStream = new FileInputStream(file);
                workbook = new HSSFWorkbook(fileInputStream);
                Sheet sheet = workbook.getSheet("0");


                int numberOfCells = 0;
                Iterator rowIterator = sheet.rowIterator();
                /**
                 * Escape the header row *
                 */
                if (rowIterator.hasNext())
                {
                    Row headerRow = (Row) rowIterator.next();
                    //get the number of cells in the header row
                    numberOfCells = headerRow.getPhysicalNumberOfCells();
                }
                System.out.println("number of cells "+numberOfCells);

}

I want the number of columns at a particular row number say 10 . The excel columns are not same

回答1:

There are two Things you can do

use

int noOfColumns = sh.getRow(0).getPhysicalNumberOfCells();

or

int noOfColumns = sh.getRow(0).getLastCellNum();

There is a fine difference between them

1. Option 1 gives the no of columns which are actually filled with contents(If the 2nd column of 10 columns is not filled you will get 9)
2. Option 2 just gives you the index of last column. Hence done 'getLastCellNum()'

回答2:

/** Count max number of nonempty cells in sheet rows */
private int getColumnsCount(XSSFSheet xssfSheet) {
    int result = 0;
    Iterator<Row> rowIterator = xssfSheet.iterator();
    while (rowIterator.hasNext()) {
        Row row = rowIterator.next();
        List<Cell> cells = new ArrayList<>();
        Iterator<Cell> cellIterator = row.cellIterator();
        while (cellIterator.hasNext()) {
            cells.add(cellIterator.next());
        }
        for (int i = cells.size(); i >= 0; i--) {
            Cell cell = cells.get(i-1);
            if (cell.toString().trim().isEmpty()) {
                cells.remove(i-1);
            } else {
                result = cells.size() > result ? cells.size() : result;
                break;
            }
        }
    }
    return result;
}