How to find whether a number belongs to a particul

问题:

This question already has an answer here:

• How do I check whether an int is between the two numbers? 7 answers

Suppose I want to check if x belongs to range 0 to 0.5. How can I do it?

回答1:

No, you can't do that. range() expects integer arguments. If you want to know if x is inside this range try some form of this:

print 0.0 <= x <= 0.5

Be careful with your upper limit. If you use range() it is excluded (range(0, 5) does not include 5!)

回答2:

print 'yes' if 0 < x < 0.5 else 'no'

range() is for generating arrays of consecutive integers

回答3:

>>> s = 1.1
>>> 0<= s <=0.2
False
>>> 0<= s <=1.2
True

回答4:

I would use the numpy library, which would allow you to do this for a list of numbers as well:

from numpy import array
a = array([1, 2, 3, 4, 5, 6,])
a[a < 2]

回答5:

To check whether some number n is in the inclusive range denoted by the two number a and b you do either

if   a <= n <= b:
    print "yes"
else:
    print "no"

use the replace >= and <= with > and < to check whether n is in the exclusive range denoted by a and b (i.e. a and b are not themselves members of the range).

Range will produce an arithmetic progression defined by the two (or three) arguments converted to integers. See the documentation. This is not what you want I guess.

回答6:

Old faithful:

if n >= a and n <= b:

And it doesn't look like Perl (joke)

回答7:

if num in range(min, max):
  """do stuff..."""
else:
  """do other stuff..."""