Cannot assign a value of type ViewController to a

问题:

Here's the error when I wrote the line self.MessageTextField.delegate = self:

/ChatApp/ViewController.swift:27:42: Cannot assign a value of type 'ViewController' to a value of type 'UITextFieldDelegate?'

Here's my Swift code (ViewerController.swift):

//
//  ViewController.swift
//  ChatApp
//
//  Created by David Chen on 15/4/12.
//  Copyright (c) 2015年 cwsoft. All rights reserved.
//

import UIKit
import Parse

class ViewController: UIViewController, UITableViewDelegate, UITableViewDataSource {

    var messagesArray:[String] = [String]()

    @IBOutlet weak var MessageTableView: UITableView!
    @IBOutlet weak var ButtonSend: UIButton!
    @IBOutlet weak var DockViewHeightConstraint: NSLayoutConstraint!
    @IBOutlet weak var MessageTextField: UITextField!

    override func viewDidLoad() {
        super.viewDidLoad()
        //
        self.MessageTableView.delegate = self
        self.MessageTableView.dataSource = self
        //Set delegate
        self.MessageTextField.delegate = self

        self.messagesArray.append("Test 1")
        self.messagesArray.append("Test 2")
        self.messagesArray.append("Test 3")
    }

    @IBAction func ButtonSendPressed(sender: UIButton) {
        self.view.layoutIfNeeded()
        UIView.animateWithDuration(0.5, animations: {
            self.DockViewHeightConstraint.constant = 400
            self.view.layoutIfNeeded()
            }, completion: nil)
    }

    //MARK : TextField Delegage Methods


    //MARK : Table View Delegate Methods

    func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {
        let cell = self.MessageTableView.dequeueReusableCellWithIdentifier("MessageCell") as! UITableViewCell
        cell.textLabel?.text = self.messagesArray[indexPath.row]
        return cell
    }

    func tableView(tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
        return messagesArray.count
    }
}

回答1:

The line self.MessageTextField.delegate = self causes the error since you try to assign self as the delegate of a UITextField.
But your ViewController is not a UITextFieldDelegate. To make your class this kind of delegte, you need to adopt the UITextFieldDelegate protocol. This can be achieved by adding it to the list of protocols and classes your class inherits from / conforms to. In your case that is done by changing the line

class ViewController: UIViewController, UITableViewDelegate, UITableViewDataSource

to

class ViewController: UIViewController, UITableViewDelegate, UITableViewDataSource, UITextFieldDelegate

回答2:

Declare that your class conforms to the UITextFieldDelegate protocol and implement any of those protocol methods that you need.

class ViewController: UIViewController, UITableViewDelegate, UITableViewDataSource, UITextFieldDelegate { ... }

回答3:

I had the same problem, but it was because of a different issue:

class CustomViewController: UIViewController {

    let customerCardTableView: UITableView = {
        let table = UITableView()
        table.translatesAutoresizingMaskIntoConstraints = false
        table.backgroundColor = UIColor(patternImage: UIImage(named: "background")!)
        table.delegate = self
        table.dataSource = self
        table.separatorStyle = .none
        table.separatorColor = UIColor(rgb:0xFFFFFF)
        table.separatorInset = UIEdgeInsets(top: 0, left: 10, bottom: 0, right: 10)

        return table
    }()

    ...other code 
}

and I did extend my CustomViewController to conform to the UITableViewDelegate, UITableViewDataSource protocols.

The reason was that self isn't accessible if you're using let. I had to lazy var customerCardTableView: UITableView i.e.:

lazy var customerCardTableView: UITableView = {
    let table = UITableView()
    table.translatesAutoresizingMaskIntoConstraints = false
    table.backgroundColor = UIColor(patternImage: UIImage(named: "background")!)
    table.delegate = self
    table.dataSource = self
    table.separatorStyle = .none
    table.separatorColor = UIColor(rgb:0xFFFFFF)
    table.separatorInset = UIEdgeInsets(top: 0, left: 10, bottom: 0, right: 10)

    return table
}()

lets are required to happen during instantiation, but lazy vars can be delayed to a time after instantiation, hence they can access self...