Same thing asked 2.5 years ago in Downloading a web page and all of its resource files in Python but doesn't lead to an answer and the 'please see related topic' isn't really asking the same thing.
I want to download everything on a page to make it possible to view it just from the files.
The command
wget --page-requisites --domains=DOMAIN --no-parent --html-extension --convert-links --restrict-file-names=windows
does exactly that I need. However we want to be able to tie it in with other stuff that must be portable, so requires it to be in Python.
I've been looking at Beautiful Soup, scrapy, various spiders posted around the place, but these all seem to deal with getting data/links in clever but specific ways. Using these to do what I want seems like it will require a lot of work to deal with finding all of the resources, when I'm sure there must be an easy way.
thanks very much
You should be using an appropriate tool for the job at hand.
If you want to spider a site and save the pages to disk, Python probably isn't the best choice for that. Open source projects get features when someone needs that feature, and because wget does its job so well, nobody has bothered to try to write a python library to replace it.
Considering wget runs on pretty much any platform that has a Python interpreter, is there a reason you can't use wget?
My colleague wrote up this code, lots pieced together from other sources I believe. Might have some specific quirks for our system but it should help anyone wanting to do the same
"""
Downloads all links from a specified location and saves to machine.
Downloaded links will only be of a lower level then links specified.
To use: python downloader.py link
"""
import sys,re,os,urllib2,urllib,urlparse
tocrawl = set([sys.argv[1]])
# linkregex = re.compile('<a\s*href=[\'|"](.*?)[\'"].*?')
linkregex = re.compile('href=[\'|"](.*?)[\'"].*?')
linksrc = re.compile('src=[\'|"](.*?)[\'"].*?')
def main():
link_list = []##create a list of all found links so there are no duplicates
restrict = sys.argv[1]##used to restrict found links to only have lower level
link_list.append(restrict)
parent_folder = restrict.rfind('/', 0, len(restrict)-1)
##a.com/b/c/d/ make /d/ as parent folder
while 1:
try:
crawling = tocrawl.pop()
#print crawling
except KeyError:
break
url = urlparse.urlparse(crawling)##splits url into sections
try:
response = urllib2.urlopen(crawling)##try to open the url
except:
continue
msg = response.read()##save source of url
links = linkregex.findall(msg)##search for all href in source
links = links + linksrc.findall(msg)##search for all src in source
for link in (links.pop(0) for _ in xrange(len(links))):
if link.startswith('/'):
##if /xxx a.com/b/c/ -> a.com/b/c/xxx
link = 'http://' + url[1] + link
elif ~link.find('#'):
continue
elif link.startswith('../'):
if link.find('../../'):##only use links that are max 1 level above reference
##if ../xxx.html a.com/b/c/d.html -> a.com/b/xxx.html
parent_pos = url[2].rfind('/')
parent_pos = url[2].rfind('/', 0, parent_pos-2) + 1
parent_url = url[2][:parent_pos]
new_link = link.find('/')+1
link = link[new_link:]
link = 'http://' + url[1] + parent_url + link
else:
continue
elif not link.startswith('http'):
if url[2].find('.html'):
##if xxx.html a.com/b/c/d.html -> a.com/b/c/xxx.html
a = url[2].rfind('/')+1
parent = url[2][:a]
link = 'http://' + url[1] + parent + link
else:
##if xxx.html a.com/b/c/ -> a.com/b/c/xxx.html
link = 'http://' + url[1] + url[2] + link
if link not in link_list:
link_list.append(link)##add link to list of already found links
if (~link.find(restrict)):
##only grab links which are below input site
print link ##print downloaded link
tocrawl.add(link)##add link to pending view links
file_name = link[parent_folder+1:]##folder structure for files to be saved
filename = file_name.rfind('/')
folder = file_name[:filename]##creates folder names
folder = os.path.abspath(folder)##creates folder path
if not os.path.exists(folder):
os.makedirs(folder)##make folder if it does not exist
try:
urllib.urlretrieve(link, file_name)##download the link
except:
print "could not download %s"%link
else:
continue
if __name__ == "__main__":
main()
thanks for the replies
