Consider the example data.frame
df <- data.frame(
id = 1:4,
name = c("Bob", "Ashley", "James", "David"),
age = c(48, NA, 40, 28),
test1_score = c(18.9, 19.5, NA, 12.9),
stringsAsFactors = FALSE)
I'm using the R package formattable to make a pretty table.
library(formattable)
formattable(df, list(
age = color_tile("white", "orange"),
test1_score = color_bar("pink", 'proportion', 0.2)
))
It used to be that NA's were automatically not printed, and a blank was printed instead. It seems like this is no longer the default, but I would still like to print a blank for the NA. Replacing NA like this works:
df[is.na(df)]=''
formattable(df, list(
age = color_tile("white", "orange"),
test1_score = color_bar("pink", 'proportion', 0.2)
))
However if I try to format one of the columns to force it to have 2 decimal places, the pesky NA's return:
df$age = digits(df$age, digits=2)
formattable(df, list(
age = color_tile("white", "orange"),
test1_score = color_bar("pink", 'proportion', 0.2)
))
If I remove the NA again, the NA goes away, but so do the decimal places
df[is.na(df)] = ''
formattable(df, list(
age = color_tile("white", "orange"),
test1_score = color_bar("pink", 'proportion', 0.2)
))
I believe the reason is that digits converts df$age
to a formattable numeric
object and creates the NA
, and df[is.na(df)] = ''
converts df$age
to a formattable character
object:
> df$age = digits(df$age, digits=2)
> df$age
[1] 48.00 NA 40.00 28.00
> class(df$age)
[1] "formattable" "numeric"
> df[is.na(df)] = ''
> df$age
[1] "48" " " "40" "28"
> class(df$age)
[1] "formattable" "character"
Any ideas on a solution?
Ultimately I'd also like to use this with a filtered data.frame, where I use the code from Filtering dataframes with formattable to ensure that the color scale stays the same when filtering the data.frame:
df$age = digits(df$age, digits=2)
subset_df <- function(m) {
formattable(df[m, ], list(
age = x ~ color_tile("white", "orange")(df$age)[m],
test1_score = x ~ color_bar("pink", 'proportion', 0.2)(df$test1_score)[m],
test2_score = x ~ color_bar("pink", 'proportion', 0.2)(df$test2_score)[m]
))
}
subset_df(1:3)
The problem doesn't seem to be with this code though.