How to raise a 410 error in Django

2020-06-14 03:22发布

问题:

I'd like to return 410 errors at for some of my Django pages instead of returning 404s. Basically, instead of calling raise Http404('some error message'), I would like to instead call raise Http410('some error message') shortcut.

I am confused because in django.http, the function Http404 is simply:

class Http404(Exception):
    pass

So if I do the same thing and create my Http410 function, I would assume it would look like:

class Http410(Exception):
    pass

However, doing this returns the exception but serves up a 500 error page. How do I recreate the magic of the Http404 exception? I should note, I need to raise the exception from my models (not views) so I can't just return an HttpResponseGone.

Thanks in advance!

Update: I am fully aware of HttpResponseGone and mentioned this in my original question. I already know how to return this in my views. My question is: How do you raise an Http 410 exception similarly to how you raise an Http 404 exception? I want to be able to raise this exception anywhere, not just in my views. Thanks!

回答1:

Django does not include a mechanism for this because gone should be normal workflow, not an error condition, but if you want to not treat it as a return response, and as an exception, just implement a middleware.

class MyGoneMiddleware(object):
    def process_exception(self, request, exception):
        if isinstance(exception, Http410):
            return HttpResponseGone("Gone!")
        return None


回答2:

from django.http import HttpResponse
return HttpResponse(status=410)


回答3:

Return a HttpResponseGone, a subclass of HttpResponse, in your view handler.