constexpr
functions are not supposed to contain:
A definition of a variable of non-literal type
But in this answer a lambda is defined in one: https://stackoverflow.com/a/41616651/2642059
template <typename T>
constexpr auto make_div(const T quot, const T rem)
{
return [&]() {
decltype(std::div(quot, rem)) result;
result.quot = quot;
result.rem = rem;
return result;
}();
}
and in my comment I define a div_t
in one: How can I Initialize a div_t Object?
template <typename T>
constexpr decltype(div(T{}, T{})) make_div(const T quot, const T rem)
{
decltype(div(T{}, T{})) x{};
x.quot = quot;
x.rem = rem;
return x;
}
Exactly what is meant by the prohibition of the "definition of a variable of non-literal type"?
Visual Studio 2015 won't allow my definition of a div_t
but I find it nonsensical that it would be allowable to just wrap such illegitimate behavior in a lambda and execute it. I'd like to know which if either of the compilers are behaving correctly with respect to the div_t
definition.
It's virtually guaranteed that if there's a discrepancy gcc has the correct behavior, because Visual Studio 2015 doesn't support c++14's extension of constexpr
: https://msdn.microsoft.com/en-us/library/hh567368.aspx#C-14-Core-Language-Features
C++11 constexpr
functions
The function body can only contain:
- null statements (plain semicolons)
static_assert
declarations
typedef
declarations and alias declarations that do not define classes or enumerations
using
declarations
using
directives
- exactly one
return
statement
So c++11 cannot tolerate the definition of decltype(div(T{}, T{})) x{}
. It would however be acceptable to roll the ternary suggested here in a constexpr
function to achieve the same results:
template <typename T>
constexpr auto make_div(const T quot, const T rem)
{
using foo = decltype(div(T{}, T{}));
return foo{1, 0}.quot != 0 ? foo{quot, rem} : foo{rem, quot};
}
Live Example
C++14 constexpr
functions
The function body may contain anything but:
- an asm declaration
- a goto statement
- a statement with a label other than case and default
- a try-block
- a definition of a variable of non-literal type
- a definition of a variable of static or thread storage duration
- a definition of a variable for which no initialization is performed
Where a "Literal Type" is defined here, specifically for objects though, they may be aggregate types with a trivial destructor. So div_t
definitely qualifies. Thus c++14, and by extension gcc, can tolerate the definition of decltype(div(T{}, T{})) x{}
.
C++17 constexpr
functions
C++17 added support for closure types to the definition of "Literal Type", so I find it strange that both gcc and Visual Studio support the use of the lambda in the return
statement. I guess that's either forward looking support or the compiler chose to inline the lambda. In either case I don't think that it qualifies as a c++14 constexpr
function.
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