Is there a C++ macro that obtains the current namespace and function name? Example:
namespace foo {
namespace bar {
void baz(int i, double d) {
std::cout << MACRO << std::endl;
}
}
}
would print foo::bar::baz
. I know of __FUNCTION__
but it doesn't give the namespace. And BOOST_CURRENT_FUNCTION
gives the whole signature, incl. arguments and return type:
void foo::bar::baz(int, double)
Maybe, is it possible to write a macro that extracts the namespace and function name from BOOST_CURRENT_FUNCTION
?
I want that for logging purposes, to get a logging string like
foo::bar::baz -- blah logging message blah
As far as I know, it's not possible (not portably). However from the full signature you can extract those arguments. Of course it requires parsing said signature... which is not so easy :x
Here is the function I use at the moment:
// What we want to consume:
// void
// signed short
// unsigned int
// Test::Bar<T, N>
//
static char const* consumeType(char const* const begin, char const* const end){
static StringRef const Signed("signed");
static StringRef const Unsigned("unsigned");
char const* it = begin;
if (startsWith(it, Signed)) { it += Signed.size() + 1; }
else if (startsWith(it, Unsigned)) { it += Unsigned.size() + 1; }
// jump over the return type
size_t templateNest = 0;
while (it != end) {
if (*it == ' ' and templateNest == 0) { break; }
if (*it == '<') { ++templateNest; }
if (*it == '>' and templateNest > 0) { --templateNest; }
++it;
}
return it;
} // consumeType
//
// \param signature: signature as returned by __func___ on gcc
// \return: full name, included namespace qualifier and class (if any)
//
// void Test::Bar<T, N>::parameterized(U) const
// [with unsigned int O = 4u, U = Test::Foo,
// T = Test::Foo, unsigned int N = 3u]
// -> Test::Bar<T, N>::parameterized
//
StringRef parseFunctionName(StringRef const signature) {
char const* begin = signature.begin();
char const* end = signature.end();
// Jump over the return type
begin = consumeType(begin, end);
if (begin == end) { return signature; }
// skip the space right after the return type
++begin;
if (begin == end) { return signature; }
// if we encounter a '(' then it means that we return a function,
// and we once again need to jump over the return type
if (*begin == '(') {
begin = consumeType(++begin, end);
// skip the space
++begin;
if (begin == end) { return signature; }
}
// and finally, we got the beginning, and we need to get the end, which is
// the first opening '('
char const* e = std::find(begin, end, '(');
return StringRef(begin, e - begin);
} // parseFunctionName
And its accompagnying tests:
#define UT_FUNCTION_CHECK(Signature_, Name_) \
UT_CHECK(parseFunctionName(StringRef(Signature_)) == Name_);
void Function() {
// Regular functions
UT_FUNCTION_CHECK("int main()", "main")
UT_FUNCTION_CHECK("int foo(int, double)", "foo")
UT_FUNCTION_CHECK("unsigned int foo(int, double)", "foo")
// Templates
UT_FUNCTION_CHECK("unsigned int Test::Bar<T, N>::print() const"
" [with T = Test::Foo, unsigned int N = 3u]",
"Test::Bar<T, N>::print")
UT_FUNCTION_CHECK("Test::Bar<T, N> Test::Bar<T, N>::print() const"
" [with T = Test::Foo, unsigned int N = 3u]",
"Test::Bar<T, N>::print")
UT_FUNCTION_CHECK("void Test::Bar<T, N>::parameterized(U) const"
" [with unsigned int O = 4u, U = Test::Foo,"
" T = Test::Foo, unsigned int N = 3u]",
"Test::Bar<T, N>::parameterized")
// Functions returning functions
UT_FUNCTION_CHECK("void (* Test::Foo::func() const)()",
"Test::Foo::func")
UT_FUNCTION_CHECK("void (Test::Foo::* Test::Foo::method() const)(int)volatile",
"Test::Foo::method")
UT_FUNCTION_CHECK("void (Test::Foo::* Test::Foo::super())"
"(void (Test::Foo::*)(int)volatile)const",
"Test::Foo::super")
} // Function
It works in combination with gcc's __func__
macro.
The StringRef
class is similar to llvm::StringRef
.
I think it should cover your needs if you can afford the extra parsing. It's quite fast: no backtracking and no dynamic allocation, so should not be an issue (especially compared to writing to a file...).
Hope it helps.