spring data jpa composite key duplicate key record

2020-06-04 17:11发布

问题:

I have one entity having composite key and I am trying to persist it by using spring data jpa repository to mysql databse as given below:

@Embeddable
public class MobileVerificationKey implements Serializable{
private static final long serialVersionUID = 1L;

@Column(name="CUSTOMERID")
private Long customerId;

@Column(name="CUSTOMERTYPE")
private Integer customerType;

@Column(name="MOBILE")
private Long mobile;
@Embeddable
public class MobileVerificationKey implements Serializable{

    private static final long serialVersionUID = 1L;

    @Column(name="CUSTOMERID")
    private Long customerId;

    @Column(name="CUSTOMERTYPE")
    private Integer customerType;

    @Column(name="MOBILE")
    private Long mobile;
//getter and setters
}

And Entity as

@Entity
@Table(name="mobileverificationdetails")
public class MobileVerificationDetails {

    @EmbeddedId
    private MobileVerificationKey key;

    @Column(name="MOBILETYPE")
    private String mobileType;

    @Column(name="MOBILEPIN")
    private Integer mobilePin;
//getters and setters

}

My spring data jpa repository look like this:

public interface MobileVerificationDetailsRepository extends
        CrudRepository<MobileVerificationDetails, MobileVerificationKey> {

    @Override
    MobileVerificationDetails save(MobileVerificationDetails mobileVerificationDetails);

    @Override
    MobileVerificationDetails  findOne(MobileVerificationKey id);
}

Now if I am trying to add duplicate record with same key for original record and different values for other fields .when i try to insert second record it results in update of existing record with new values instead of throwing exception for violating primary key constraint...can any one please explain me this behavior.

回答1:

The easiest (and least invasive) way to work around this is probably by making sure the id only gets set right before the persist. This can be achieved in a @PrePersist callback:

abstract class MobileVerificationDetails {

  @EmbeddedId
  private MobileVerificationKey id;

  @PrePersist
  void initIdentifier() {

    if (id == null) {
      this.id = … // Create ID instance here.
    }
  }
}

Alternatively to that you can enforce persist(…) being used by implementing Persistable and implementing isNew() accordingly. Make sure this method returns true on first insert. We usually see people holding a transient boolean flag that is updated in an @PostPersist/@PostLoad annotated method.

abstract class AbstractEntity<ID extends Serializable> implements Persistable<ID> {

  private @Transient boolean isNew = true;

  @Override
  public boolean isNew() {
    return isNew;
  }

  @PostPersist
  @PostLoad
  void markNotNew() {
    this.isNew = false;
  }
}


回答2:

Spring Data Jpa Repository functionality is implemented via the SimpleJpaRepository class containing following save(..) method:

@Transactional
public <S extends T> S save(S entity) {

    if (entityInformation.isNew(entity)) {
        em.persist(entity);
        return entity;
    } else {
        return em.merge(entity);
    }
}

Thus the Spring Jpa Data Repository save(...) method merges an already existing entity.

Opposed to that the naked EntityManager#persist() throws an exception if invoked with already existing entity.

The problem might be solved by adding custom behavior to Spring Data Repository/ies. The custom behavior might be added using one of the approaches as described in 1.3.1 Adding custom behavior to single repositories with example here or in 1.3.2 Adding custom behavior to all repositories with example here. In both cases the custom behavior would include a new persist() method delegating to EntityManager#persist(). Note that in approach 1.3.2. you already have a EntityManager instance, in the approach 1.3.1 you are able to inject EntityManager instance using the @PersistenceContext.

Opposed to my comment I would recommend adding new method to the repository and not overwriting the existing save(...).