I am trying to implement a simple routine using semaphores that will allow me to run only 3 instances of the application. I could use 3 mutexes but that is not a nice approach i tried this so far
var
hSem:THandle;
begin
hSem := CreateSemaphore(nil,3,3,'MySemp3');
if hSem = 0 then
begin
ShowMessage('Application can be run only 3 times at once');
Halt(1);
end;
How can i do this properly ?
Always make sure that you release a semaphore because this is not done automatically if your application dies.
program Project72;
{$APPTYPE CONSOLE}
uses
Windows,
SysUtils;
var
hSem: THandle;
begin
try
hSem := CreateSemaphore(nil, 3, 3, 'C15F8F92-2620-4F3C-B8EA-A27285F870DC/myApp');
Win32Check(hSem <> 0);
try
if WaitForSingleObject(hSem, 0) <> WAIT_OBJECT_0 then
Writeln('Cannot execute, 3 instances already running')
else begin
try
// place your code here
Writeln('Running, press Enter to stop ...');
Readln;
finally ReleaseSemaphore(hSem, 1, nil); end;
end;
finally CloseHandle(hSem); end;
except
on E: Exception do
Writeln(E.ClassName, ': ', E.Message);
end;
end.
You could use TJclAppInstances
from the JCL.
- You must try to see if it was created
- You must use one of the wait function to see if you can get a count
- At the end, you must release the lock & handle so that it can work the next time user close and open your app
Cheers
var
hSem: THandle;
begin
hSem := OpenSemaphore(nil, SEMAPHORE_ALL_ACCESS, True, 'MySemp3');
if hSem = 0 then
hSem := CreateSemaphore(nil, 3, 3,'MySemp3');
if hSem = 0 then
begin
ShowMessage('... show the error');
Halt(1);
Exit;
end;
if WaitForSingleObject(hSem, 0) <> WAIT_OBJECT_0 then
begin
CloseHandle(hSem);
ShowMessage('Application can be runed only 3 times at once');
Halt(1);
Exit;
end;
try
your application.run codes..
finally
ReleaseSemaphore(hSem, 1, nil);
CloseHandle(hSem);
end;