I tried this way:
@ViewChild('draggable') private draggableElement: ElementRef;
this.draggableElement.nativeElement.remove();
HTML:
<div #draggable>Block</div>
I tried this way:
@ViewChild('draggable') private draggableElement: ElementRef;
this.draggableElement.nativeElement.remove();
HTML:
<div #draggable>Block</div>
Your code will also worked, only you have to do that is remove element on OnInit(), If you try to remove elements on constructor then that time view not be ready.
here's is an example
in .html
<div #draggable>Block</div>
and in .ts
export class AppComponent implements OnInit {
name="Angular";
@ViewChild('draggable') private draggableElement: ElementRef;
constructor() { }
ngOnInit() {
this.draggableElement.nativeElement.remove();
}
}
here's is an Stackblitz demo
User Renderer2 service to remove element from dom
removeChild() Implement this callback to remove a child node from the host element's DOM.
@ViewChild('draggable') draggableElement: ElementRef;
constructor(private renderer2: Renderer2,private el:ElementRef) {}
ngOnInit() {
this.renderer2.removeChild(this.el.nativeElement,this.draggableElement.nativeElement);
}
Example:https://stackblitz.com/edit/angular-renderer2-remove
You can use *ngIf right, which will be removed from the DOM when condition fails.
Block