MVC: How to get controller to render partial view

问题:

In my MVC5 project I want to create a menu in a partial view. This menu is dynamic in the sense that it is built from content in my database. Thus I have a controller taking care of creating my menu and returning the menu model to my partial view:

public PartialViewResult GetMenu()
{
   MenuStructuredModel menuStructuredModel = menuBusiness.GetStructuredMenu();

   return PartialView("~/Views/Shared/MenuPartial", menuStructuredModel);
}

In my partial view called MenuPartial I want to use razor to iterate over my menu items, like:

@model MyApp.Models.Menu.MenuStructuredModel

<div class="list-group panel">
    @foreach (var category in Model.ViewTypes[0].Categories)
    {
        <a href="#" class="list-group-item lg-green" data-parent="#MainMenu">@category.ShownName</a>
    }
</div>

Now the problem is the view in which I insert the partial view. If in the view I simply do:

@Html.Partial("MenuPartial")

It won't call the controller to populate the model with data first. What I want is to let the controller return the partial. But I don't know how to do this from the view. In pseudo code I would like to do something like:

@Html.RenderPartialFromController("/MyController/GetMenu")

回答1:

Thanks to Stephen Muecke and Erick Cortorreal I got it to work.

This is what the controller should look like:

[ChildActionOnly]
public PartialViewResult GetMenu()
{
   MenuStructuredModel menuStructuredModel = menuBusiness.GetStructuredMenu();

   return PartialView("~/Views/Shared/MenuPartial", menuStructuredModel);
}

And it may called like:

@Html.Action("GetMenu", "Home")

(Hence GetMenu() is declared in the HomeController in my example).

The controller is now called (and the model is populated) prior to the partial view is rendered.

回答2:

You should use: @Html.RenderAction or @Html.Action.