Currently I have a useLazyQuery
hook which is fired on a button press (part of a search form).
The hook behaves normally, and is only fired when the button is pressed. However, once I've fired it once, it's then fired every time the component re-renders (usually due to state changes).
So if I search once, then edit the search fields, the results appear immediately, and I don't have to click on the search button again.
Not the UI I want, and it causes an error if you delete the search text entirely (as it's trying to search with null
as the variable), is there any way to prevent the useLazyQuery
from being refetched on re-render?
This can be worked around using useQuery
dependent on a 'searching' state which gets toggled on when I click on the button. However I'd rather see if I can avoid adding complexity to the component.
const AddCardSidebar = props => {
const [searching, toggleSearching] = useState(false);
const [searchParams, setSearchParams] = useState({
name: ''
});
const [searchResults, setSearchResults] = useState([]);
const [selectedCard, setSelectedCard] = useState();
const [searchCardsQuery, searchCardsQueryResponse] = useLazyQuery(SEARCH_CARDS, {
variables: { searchParams },
onCompleted() {
setSearchResults(searchCardsQueryResponse.data.searchCards.cards);
}
});
...
return (
<div>
<h1>AddCardSidebar</h1>
<div>
{searchResults.length !== 0 &&
searchResults.map(result => {
return (
<img
key={result.scryfall_id}
src={result.image_uris.small}
alt={result.name}
onClick={() => setSelectedCard(result.scryfall_id)}
/>
);
})}
</div>
<form>
...
<button type='button' onClick={() => searchCardsQuery()}>
Search
</button>
</form>
...
</div>
);
};