I want to find the sub-image from large image using PIL library. I also want to know the coordinates where it is found ?
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问题:
回答1:
import cv2
import numpy as np
image = cv2.imread("Large.png")
template = cv2.imread("small.png")
result = cv2.matchTemplate(image,template,cv2.TM_CCOEFF_NORMED)
print np.unravel_index(result.argmax(),result.shape)
This works fine and in efficient way for me.
回答2:
I managed to do this only using PIL.
Some caveats:
- This is a pixel perfect search. It simply looks for matching RGB pixels.
- For simplicity I remove the alpha/transparency channel. I'm only looking for RGB pixels.
- This code loads the entire subimage pixel array into memory, while keeping the large image out of memory. On my system Python maintained a ~26 MiB memory footprint for a tiny 40x30 subimage searching through a 1920x1200 screenshot.
- This simple example isn't very efficient, but increasing efficiency will add complexity. Here I'm keeping things straight forward and easy to understand.
- This example works on Windows and OSX. Not tested on Linux. It takes a screenshot of the primary display only (for multi monitor setups).
Here's the code:
import os
from itertools import izip
from PIL import Image, ImageGrab
def iter_rows(pil_image):
"""Yield tuple of pixels for each row in the image.
From:
http://stackoverflow.com/a/1625023/1198943
:param PIL.Image.Image pil_image: Image to read from.
:return: Yields rows.
:rtype: tuple
"""
iterator = izip(*(iter(pil_image.getdata()),) * pil_image.width)
for row in iterator:
yield row
def find_subimage(large_image, subimg_path):
"""Find subimg coords in large_image. Strip transparency for simplicity.
:param PIL.Image.Image large_image: Screen shot to search through.
:param str subimg_path: Path to subimage file.
:return: X and Y coordinates of top-left corner of subimage.
:rtype: tuple
"""
# Load subimage into memory.
with Image.open(subimg_path) as rgba, rgba.convert(mode='RGB') as subimg:
si_pixels = list(subimg.getdata())
si_width = subimg.width
si_height = subimg.height
si_first_row = tuple(si_pixels[:si_width])
si_first_row_set = set(si_first_row) # To speed up the search.
si_first_pixel = si_first_row[0]
# Look for first row in large_image, then crop and compare pixel arrays.
for y_pos, row in enumerate(iter_rows(large_image)):
if si_first_row_set - set(row):
continue # Some pixels not found.
for x_pos in range(large_image.width - si_width + 1):
if row[x_pos] != si_first_pixel:
continue # Pixel does not match.
if row[x_pos:x_pos + si_width] != si_first_row:
continue # First row does not match.
box = x_pos, y_pos, x_pos + si_width, y_pos + si_height
with large_image.crop(box) as cropped:
if list(cropped.getdata()) == si_pixels:
# We found our match!
return x_pos, y_pos
def find(subimg_path):
"""Take a screenshot and find the subimage within it.
:param str subimg_path: Path to subimage file.
"""
assert os.path.isfile(subimg_path)
# Take screenshot.
with ImageGrab.grab() as rgba, rgba.convert(mode='RGB') as screenshot:
print find_subimage(screenshot, subimg_path)
Speed:
$ python -m timeit -n1 -s "from tests.screenshot import find" "find('subimg.png')"
(429, 361)
(465, 388)
(536, 426)
1 loops, best of 3: 316 msec per loop
While running the above command I moved the window containing the subimage diagonally as timeit
was running.
回答3:
It sounds like you want to perform object detection, probably via template matching. It's not a trivial problem unless you're looking for an exact pixel-by-pixel match, and PIL is not meant to do this sort of thing.
Jan is right that you should try OpenCV. It's a robust computer vision library with good Python bindings.
Here's a nice short example in Python that draws a rectangle around the matched region: https://github.com/jungilhan/Tutorial/blob/master/OpenCV/templateMatching.py