How to print the memory address of a slice in Gola

2020-05-25 07:36发布

问题:

I have some experience in C and I am totally new to golang.

func learnArraySlice() {
  intarr := [5]int{12, 34, 55, 66, 43}
  slice := intarr[:]
  fmt.Printf("the len is %d and cap is %d \n", len(slice), cap(slice))
  fmt.Printf("address of slice 0x%x add of Arr 0x%x \n", &slice, &intarr)
}

Now in golang slice is a reference of array which contains the pointer to an array len of slice and cap of slice but this slice will also be allocated in memory and i want to print the address of that memory. But unable to do that.

回答1:

http://golang.org/pkg/fmt/

fmt.Printf("address of slice %p add of Arr %p \n", &slice, &intarr)

%p will print the address.



回答2:

Slices and their elements are addressable:

s := make([]int, 10)
fmt.Printf("Addr of first element: %p\n", &s[0])
fmt.Printf("Addr of slice itself:  %p\n", &s)


回答3:

For the addresses of the slice underlying array and the array (they are the same in your example),

package main

import "fmt"

func main() {
    intarr := [5]int{12, 34, 55, 66, 43}
    slice := intarr[:]
    fmt.Printf("the len is %d and cap is %d \n", len(slice), cap(slice))
    fmt.Printf("address of slice %p add of Arr %p\n", &slice[0], &intarr)
}

Output:

the len is 5 and cap is 5 
address of slice 0x1052f2c0 add of Arr 0x1052f2c0