Check if a string is encoded in base64 using Pytho

问题:

Is there a good way to check if a string is encoded in base64 using Python?

回答1:

This isn't possible. The best you could do would be to verify that a string might be valid Base 64, although many strings consisting of only ASCII text can be decoded as if they were Base 64.

回答2:

import base64
import binascii

try:
    base64.decodestring("foo")
except binascii.Error:
    print "no correct base64"

回答3:

I was looking for a solution to the same problem, then a very simple one just struck me in the head. All you need to do is decode, then re-encode. If the re-encoded string is equal to the encoded string, then it is base64 encoded.
Here is the code:

import base64

def isBase64(s):
    try:
        return base64.b64encode(base64.b64decode(s)) == s
    except Exception:
        return False

That's it!

Edit: Here's a version of the function that works with both the string and bytes objects in Python 3:

import base64

def isBase64(sb):
        try:
                if isinstance(sb, str):
                        # If there's any unicode here, an exception will be thrown and the function will return false
                        sb_bytes = bytes(sb, 'ascii')
                elif isinstance(sb, bytes):
                        sb_bytes = sb
                else:
                        raise ValueError("Argument must be string or bytes")
                return base64.b64encode(base64.b64decode(sb_bytes)) == sb_bytes
        except Exception:
                return False

回答4:

The solution I used is based on one of the prior answers, but uses more up to date calls.

In my code, the my_image_string is either the image data itself in raw form or it's a base64 string. If the decode fails, then I assume it's raw data.

Note the validate=True keyword argument to b64decode. This is required in order for the assert to be generated by the decoder. Without it there will be no complaints about an illegal string.

import base64, binascii

try:
    image_data = base64.b64decode(my_image_string, validate=True)
except binascii.Error:
    image_data = my_image_string

回答5:

if the length of the encoded string is the times of 4, it can be decoded

base64.encodestring("whatever you say").strip().__len__() % 4 == 0

so, you just need to check if the string can match something like above, then it won't throw any exception(I Guess =.=)

if len(the_base64string.strip()) % 4 == 0:
    # then you can just decode it anyway
    base64.decodestring(the_base64string)

回答6:

def is_base64(s):
    s = ''.join([s.strip() for s in s.split("\n")])
    try:
        enc = base64.b64encode(base64.b64decode(s)).strip()
        return enc == s
    except TypeError:
        return False

In my case, my input, s, had newlines which I had to strip before the comparison.

回答7:

@geoffspear is correct in that this is not 100% possible but you can get pretty close by checking the string header to see if it matches that of a base64 encoded string (re: How to check whether a string is base64 encoded or not).

# check if a string is base64 encoded.
def isBase64Encoded(s):
    pattern = re.compile("^([A-Za-z0-9+/]{4})*([A-Za-z0-9+/]{4}|[A-Za-z0-9+/]{3}=|[A-Za-z0-9+/]{2}==)$")
    if not s or len(s) < 1:
        return False
    else:
        return pattern.match(s)

Also not that in my case I wanted to return false if the string is empty to avoid decoding as there's no use in decoding nothing.

回答8:

x = 'possibly base64 encoded string'
result = x
try:
   decoded = x.decode('base64', 'strict')
   if x == decoded.encode('base64').strip():
       result = decoded
except:
   pass

this code put in the result variable decoded string if x is really encoded, and just x if not. Just try to decode doesn't always work.

回答9:

Using Python RegEx

import re

txt = "VGhpcyBpcyBlbmNvZGVkIHRleHQ="
x = re.search("^([A-Za-z0-9+/]{4})*([A-Za-z0-9+/]{3}=|[A-Za-z0-9+/]{2}==)?$", txt)

if (x):
  print("Encoded")
else:
  print("Non encoded")