How to access URL segment(s) in blade in Laravel 5

问题:

I have a url : http://localhost:8888/projects/oop/2

I want to access the first segment --> projects

I've tried

<?php echo $segment1 = Request::segment(1); ?>

I see nothing print out in my view when I refresh my page.

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Any helps / suggestions will be much appreciated

回答1:

Try this

{{ Request::segment(1) }}

回答2:

The double curly brackets are processed via Blade -- not just plain PHP. This syntax basically echos the calculated value.

{{ Request::segment(1) }} 

回答3:

BASED ON LARAVEL 5.7 & ABOVE

To get all segments of current URL:

$current_uri = request()->segments();

To get segment posts from http://example.com/users/posts/latest/

NOTE: Segments are an array that starts at index 0. The first element of array starts after the TLD part of the url. So in the above url, segment(0) will be users and segment(1) will be posts.

//get segment 0
$segment_users = request()->segment(0); //returns 'users'
//get segment 1
$segment_posts = request()->segment(1); //returns 'posts'

You may have noted that the segment method only works with the current URL ( url()->current() ). So I designed a method to work with previous URL too by cloning the segment() method:

public function index()
{
    $prev_uri_segments = $this->prev_segments(url()->previous());
}

 /**
 * Get all of the segments for the previous uri.
 *
 * @return array
 */
public function prev_segments($uri)
{
    $segments = explode('/', str_replace(''.url('').'', '', $uri));

    return array_values(array_filter($segments, function ($value) {
        return $value !== '';
    }));
}

回答4:

Here is how one can do it via the global request helper function.

{{ request()->segment(1) }}

Note: request() returns the object of the Request class.

回答5:

Here is code you can get url segment.

{{ Request::segment(1) }}

If you don't want the data to be escaped then use {!! !!} else use {{ }}.

{!! Request::segment(1) !!}

https://laravel.com/docs/4.2/requests