Most elegant way to ensure view model data for _La

2020-05-23 09:08发布

问题:

In my application I have some basic user information that needs to be displayed on every page (name, profile img). At the moment I have simply set the model in the _Layout.cshtml page to be a class called ApplicationBaseModel and every other view model throughout the application must inherit from this class, and every action must set the appropriate data for the base model.

I don't mind simple inheritance in this way, it is the fact that in every single action method I must retreive the data and store it in the view model. Not a very elegant solution in my opinion.

Anyone have any ideas on other ways of solving this issue?

回答1:

I would create a BaseController which retrieves the data in the Initialize() override and sets it to a ViewBag property. Now derive every Controller you create from BaseController and in your layout use the ViewBag property to access your user data.

public class BaseController : Controller
{
    protected override void Initialize(System.Web.Routing.RequestContext requestContext)
    {
        base.Initialize(requestContext);

        // retireve data
        var data = new ApplicationBaseModel();

        // set to viewbag
        ViewBag.UserData = data;
    }
}

This way you do not have to derive all your model classes from ApplicationBaseModel. You can have strongly typed views and additionally your user data as a ViewBag property.



回答2:

Depending on when you want to generate the ViewBag data you could also use the functions OnActionExecuting or OnActionExecuted. This might be more suitable because some data might not be available at the time the Controller is created.

public class MyController : Controller
{
    //Executes before every action
    protected override void OnActionExecuting(ActionExecutedContext context) 
    {
        //Call the method from the base class
        base.OnActionExecuting(context);

        //Create the ViewBag data here
        ViewBag.XYZ = XYZ();
    }

    //Executes after every action
    protected override void OnActionExecuted(ActionExecutedContext context) 
    {
        //Call the method from the base class
        base.OnActionExecuted(context);

        //Create the ViewBag data here
        ViewBag.XYZ = XYZ();

    }
}


回答3:

Another option would be to rip out the parts of the layout view that require data, and place them into partials. Then from your layout view make an Html.Action call to actions that return those partials with the necessary viewmodel data.