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问题:
In django RestFramework, is there any "official" way to generate the documentation for the "Api Root" ?
After looking at the RestFramework's source code, I've found a work around by subclassing the DefaultRouter:
from rest_framework import routers
class MyRouter(routers.DefaultRouter):
def get_api_root_view(self):
api_root_view = super(MyRouter, self).get_api_root_view()
ApiRootClass = api_root_view.cls
class MyAPIRoot(ApiRootClass):
"""My API Root documentation"""
pass
return MyAPIRoot.as_view()
router = MyRouter()
Is there a cleaner or better way ?
回答1:
I'm new to this but I found you can use a SimpleRouter
instead of a DefaultRouter
to specify your own APIRoot
.
in urls.py
in your api module
from django.conf.urls import patterns, url, include
from rest_framework.routers import SimpleRouter
router = SimpleRouter()
urlpatterns = patterns('api.views',
url(r'^$', views.APIRoot.as_view()),
url(r'', include(router.urls)),
)
Then specify the documentation in the class comment
from rest_framework import generics
class APIRoot(generics.GenericAPIView):
"""
My API documentation
"""
ㄑ
回答2:
I found a solution through experimentation.
I prefer it to the other solutions in this thread as it requires less code and allows you to customise the API title, as well as the documentation for the API root.
from rest_framework import routers
class ThisWillBeTheApiTitleView(routers.APIRootView):
"""
This appears where the docstring goes!
"""
pass
class DocumentedRouter(routers.DefaultRouter):
APIRootView = ThisWillBeTheApiTitleView
router = DocumentedRouter()
router.register(r'items', ItemsViewSet)
This renders as below:
回答3:
If anyone wants an inline style
router = DefaultRouter()
router.get_api_root_view().cls.__name__ = "Root API name"
router.get_api_root_view().cls.__doc__ = "Your Description"
回答4:
It's kind of difficult to override the APIRoot class. The most simple way to achieve what you want is probably to modify the __doc__
attribute of the APIRootClass at runtime in your urls.py
:
class Router(routers.DefaultRouter):
def get_api_root_view(self, api_urls=None):
root_view = super(Router, self).get_api_root_view(api_urls=api_urls)
root_view.cls.__doc__ = "Place your documentation here"
return root_view
router = Router()
router.register(...)
urlpatterns = [
url(r'^', include(router.urls)),
]
回答5:
@api_view(['GET'])
def api_root(request, format=None):
return Response({
'users': reverse('user-list', request=request, format=format),
'snippets': reverse('snippet-list', request=request, format=format)
})
回答6:
Thanks to frost-nzcr4's comment above, I found a nice way to do this:
from rest_framework import routers
from django.utils.safestring import mark_safe
class MyAPIRootView(routers.APIRootView):
"""
Controls appearance of the API root view
"""
def get_view_name(self) -> str:
return "My API"
def get_view_description(self, html=False) -> str:
text = "My REST API"
if html:
return mark_safe(f"<p>{text}</p>")
else:
return text
class MyRouter(routers.DefaultRouter):
APIRootView = MyAPIRootView
Then use this router in your urls.py
:
router = MyRouter()