Convert StreamResult to string or xml

问题:

Using spring ws to get the StreamResult as below

StreamSource source = new StreamSource(new StringReader(MESSAGE));
StreamResult result = new StreamResult(System.out);
webServiceTemplate.sendSourceAndReceiveToResult("http://someUri", 
                source, new SoapActionCallback("someCallBack"), result); 
return result;

I get the result, But I want to extract it to some sort of xml or even as a string (Just want to see the contents in order to generate the response).

How can I do this?

回答1:

Try this one:

try {
    StreamSource source = new StreamSource(new StringReader("<xml>blabla</xml>"));
    StringWriter writer = new StringWriter();
    StreamResult result = new StreamResult(writer);
    TransformerFactory tFactory = TransformerFactory.newInstance();
    Transformer transformer = tFactory.newTransformer();
    transformer.transform(source,result);
    String strResult = writer.toString();
} catch (Exception e) {
    e.printStackTrace();
}

回答2:

You can get the reader of your StreamSource by using getReader(). You should then be able to use read(char[] cbuf) to write the contents of the stream to a character array which can easily be converted into a string and printed to the console if you wish.

回答3:

If none of these works, try this

System.out.println(result.getOutputStream().toString());

Assuming you have this kind of structure ,

private static StreamResult printSOAPResponse(SOAPMessage soapResponse) throws Exception {
    TransformerFactory transformerFactory = TransformerFactory.newInstance();
    Transformer transformer = transformerFactory.newTransformer();
    Source sourceContent = soapResponse.getSOAPPart().getContent();
    System.out.print("\nResponse SOAP Message = ");
    StreamResult result = new StreamResult(System.out);
    transformer.transform(sourceContent, result);
    return result;
}

You can try this way , although the same thing, wanted to point it out clearly

System.out.println(printSOAPResponse(soapResponse).getOutputStream().toString());

回答4:

If you use Spring you could also use this way:

    import org.springframework.core.io.Resource;
    import org.apache.commons.io.IOUtils;
    ....    
    @Value("classpath:/files/dummyresponse.xml")
    private Resource dummyResponseFile;
    ....
    public String getDummyResponse() {
        try {
            if (this.dummyResponse == null)
                dummyResponse = IOUtils.toString(dummyResponseFile.getInputStream(),StandardCharsets.UTF_8);
        }  catch (IOException e) {
            logger.error("Fehler in Test-Service: {}, {}, {}", e.getMessage(), e.getCause(), e.getStackTrace());
            throw new RuntimeException(e);
        }
        return dummyResponse;
    }