Can I set the breakpoint/watchpoint/smth else in gdb for register value?
I want to break when $eax will have value 0x0000ffaa.
Is it possible with gdb or dbx or any other unix debugger?
Can I set the breakpoint/watchpoint/smth else in gdb for register value?
I want to break when $eax will have value 0x0000ffaa.
Is it possible with gdb or dbx or any other unix debugger?
Yes in gdb you would set a watchpoint like so:
watch $eax == 0x0000ffaa
But it is dependent on watchpoint support being available for the target. You should note that this may slow down execution significantly.
If you would like to break in a certain location you can do so, by setting a conditional breakpoint:
break test.c:120 if $eax == 0x0000ffaa
To whit:
If you use $eax the condition is ignored and it becomes an unconditional watch/breakpoint.
(gdb) disass print_hello
Dump of assembler code for function print_hello:
0x000000000040058c : push %rbp
0x000000000040058d : mov %rsp,%rbp
0x0000000000400590 : sub $0x20,%rsp
0x0000000000400594 : movl $0x1,-0x4(%rbp)
0x000000000040059b : movl $0x5,-0x4(%rbp)
0x00000000004005a2 : mov -0x4(%rbp),%esi
0x00000000004005a5 : mov $0x4006dc,%edi
0x00000000004005aa : mov $0x0,%eax
0x00000000004005af : callq 0x400468
0x00000000004005b4 : leaveq
0x00000000004005b5 : retq
End of assembler dump.
(gdb) break *0x00000000004005af if $eax==0
Breakpoint 1 at 0x4005af: file hello.c, line 7.
(gdb) info break
Num Type Disp Enb Address What
1 breakpoint keep y 0x00000000004005af in print_hello at hello.c:7
stop only if $eax==0
(gdb) run
Starting program: /home/dg/hello/hello
hello world 2
Error in testing breakpoint condition:
Invalid type combination in equality test.
Breakpoint 1, 0x00000000004005af in print_hello () at hello.c:7
7 printf("hello %d\n", value);
(gdb) condition 1 $eax != 0
(gdb) run
The program being debugged has been started already.
Start it from the beginning? (y or n) y
Starting program: /home/dg/hello/hello
hello world 2
Error in testing breakpoint condition:
Invalid type combination in equality test.
Breakpoint 1, 0x00000000004005af in print_hello () at hello.c:7
7 printf("hello %d\n", value);
(gdb)
But $rax works as it should:
(gdb) condition 1 $rax != 0
(gdb) info break
Num Type Disp Enb Address What
1 breakpoint keep y 0x00000000004005af in print_hello at hello.c:7
stop only if $rax != 0
breakpoint already hit 1 time
(gdb) run
The program being debugged has been started already.
Start it from the beginning? (y or n) y
Starting program: /home/dg/hello/hello
hello world 2
hello 5
Program exited normally.
(gdb) condition 1 $rax == 0
(gdb) run
Starting program: /home/dg/hello/hello
hello world 2
Breakpoint 1, 0x00000000004005af in print_hello () at hello.c:7
7 printf("hello %d\n", value);
(gdb)
This was all tested on gdb 6.8.50: GNU gdb (GDB; SUSE Linux Enterprise 11) 6.8.50.20081120-cvs
If you are on a 64 bit machine you have to watch $rax
, not $eax
.
I was unable to get it to watch eax directly, so I inserted a few asm instructions to store the required value to a junk variable and watch that. I was unable to convince gcc to use eax, so this code "watches" ebx instead.
#include <stdio.h>
int tmp;
int main(void)
{
int i;
printf("tmp is originally %d\n",tmp);
for(i=0;i<20;i++)
{
asm (
"cmpl $10,%ebx\n"
"jne dont\n"
"movl %ebx,tmp\n"
"dont:\n"
);
printf("%d\n",i);
printf("\nnow tmp is %d\n",tmp);
return 0;
}
Now you can "watch tmp"