How do I place nodes on the same level in DOT?

问题:

I want to render several trees simultaneously and place all root nodes and all leaf nodes on the same level.

Here's an example of what I'm trying to do. Root nodes A and X are on the same level, and so are leaf nodes B, D, and Z.

I unsuccessfully tried putting roots in one rank and leaves in another as follows:

digraph G { 
rankdir = TB;
subgraph {
A -> B
A -> C
C -> D
X -> Y
rank = same; A; X;
rank = same; B; D; Y;
} /* closing subgraph */
}

And got this outcome where everything is on the same rank.

Any suggestions about what I should be trying? I've already got roots and leaves identified.

回答1:

Putting the rank = same; ... statements in braces, e.g.:

digraph G { 
  rankdir = TB;
  subgraph {
    A -> B
    A -> C
    C -> D
    X -> Y
    // note that rank is used in the subgraph
    {rank = same; A; X;}
    {rank = same; B; D; Y;}
  } /* closing subgraph */
}

... gives the desired result:

回答2:

Here's a simple example inspired by @William John Holden's comment -

graph {
  rankdir=LR;
  a -- b -- c;
  d -- e -- f;
  b -- d; {rank = same; b; d;};
}

回答3:

The ideal structure is actually rank max and rank min. No need for a subgraph or any other shenanigans. GraphViz has explicit facilities for this.

With complex graphs, rank=same will often end up near the middle of the graph. If you mean top and bottom, say top and bottom.

digraph G { 

  rankdir = TB;

  A -> B;
  A -> C -> D;
  X -> Y;

  { rank=min; A; X; }
  { rank=max; B; D; Y; }

}