I have an entity loaded by Hibernate (via EntityManager
):
User u = em.load(User.class, id)
This class is audited by Hibernate Envers. How can I load the previous version of a User entity?
I have an entity loaded by Hibernate (via EntityManager
):
User u = em.load(User.class, id)
This class is audited by Hibernate Envers. How can I load the previous version of a User entity?
maybe this then (from AuditReader docs)
AuditReader reader = AuditReaderFactory.get(entityManager);
User user_rev1 = reader.find(User.class, user.getId(), 1);
List<Number> revNumbers = reader.getRevisions(User.class, user_rev1);
User user_previous = reader.find(User.class, user_rev1.getId(),
revNumbers.get(revNumbers.size()-1));
(I'm very new to this, not sure if I have all the syntax right, maybe the size()-1 should be size()-2?)
Here's another version that finds the previous revision relative to a "current" revision number, so it can be used even if the entity you're looking at isn't the latest revision. It also handles the case where there isn't a prior revision. (em
is assumed to be a previously-populated EntityManager)
public static User getPreviousVersion(User user, int current_rev) {
AuditReader reader = AuditReaderFactory.get(em);
Number prior_revision = (Number) reader.createQuery()
.forRevisionsOfEntity(User.class, false, true)
.addProjection(AuditEntity.revisionNumber().max())
.add(AuditEntity.id().eq(user.getId()))
.add(AuditEntity.revisionNumber().lt(current_rev))
.getSingleResult();
if (prior_revision != null)
return (User) reader.find(User.class, user.getId(), prior_revision);
else
return null
}
This can be generalized to:
public static T getPreviousVersion(T entity, int current_rev) {
AuditReader reader = AuditReaderFactory.get(JPA.em());
Number prior_revision = (Number) reader.createQuery()
.forRevisionsOfEntity(entity.getClass(), false, true)
.addProjection(AuditEntity.revisionNumber().max())
.add(AuditEntity.id().eq(((Model) entity).id))
.add(AuditEntity.revisionNumber().lt(current_rev))
.getSingleResult();
if (prior_revision != null)
return (T) reader.find(entity.getClass(), ((Model) entity).id, prior_revision);
else
return null
}
The only tricky bit with this generalization is getting the entity's id. Because I'm using the Play! framework, I can exploit the fact that all entities are Models and use ((Model) entity).id
to get the id, but you'll have to adjust this to suit your environment.
I think it would be this:
final AuditReader reader = AuditReaderFactory.get( entityManagerOrSession );
// This could probably be declared as Long instead of Object
final Object pk = userCurrent.getId();
final List<Number> userRevisions = reader.getRevisions( User.class, pk );
final int revisionCount = userRevision.size();
final Number previousRevision = userRevisions.get( revisionCount - 2 );
final User userPrevious = reader.find( User.class, pk, previousRevision );
From the docs:
AuditReader reader = AuditReaderFactory.get(entityManager);
User user_rev1 = reader.find(User.class, user.getId(), 1);
Building off of the excellent approach of @brad-mace, I have made the following changes:
So here's another solution:
public static <T> T getPreviousRevision(EntityManager entityManager, Class<T> entityClass, Object entityId, int currentRev) {
AuditReader reader = AuditReaderFactory.get(entityManager);
List<Object[]> priorRevisions = (List<Object[]>) reader.createQuery()
.forRevisionsOfEntity(entityClass, false, false)
.add(AuditEntity.id().eq(entityId))
.add(AuditEntity.revisionNumber().lt(currentRev))
.addOrder(AuditEntity.revisionNumber().desc())
.setMaxResults(1)
.getResultList();
if (priorRevisions.size() == 0) {
return null;
}
// The list contains a single Object[] with entity, revinfo, and type
return (T) priorRevision.get(0)[0];
}