Java double vs BigDecimal for latitude/longitude

2020-05-16 13:58发布

问题:

When storing latitudes/longitudes which are typically of the format: 44.087585 (i.e. max 2 numbers before the dot and 6dp) do I need to bother with bigdecimals?

回答1:

Using double has enough precision for accurate lat/lon down to inches for 6-7 decimal places. In aviation, if decimal degrees are used, they typically go to at least 7 decimal places. In our NASA simulations, lat/lon data are doubles while all other attitude and altitude are floats. In other words, the 6th decimal place for altitude isn't significant while the 6th decimal place for lat/lon is for sub-foot accuracy. You should not use float for lat/lon if you need precision down to sub-feet.

You can play around in Google Earth to see what accuracy you get by placing markers and manipulating the last decimal digit.



回答2:

double should be fine for latitudes/longitudes. BigDecimal becomes more important once you start manipulating currency or need to have more control over precision.



回答3:

If you're concerned about precision, you should probably go with BigDecimal for lots of reasons covered in this post. That said, double or float should be just fine to store what you need in terms of being able to satisfy the range of values that you need.

At just six decimal places of precision I don't think double or float will trip you up, but if you start aggregating the values in any way, the minor imprecisions can start to add up.



回答4:

A double has enough precision for storing that. However, when displaying to users, use a format string like %.6f so that you don't print garbage digits out.



回答5:

if you want to control nano-robots in their nano-travels using nano-GPS - go for BigDecimal. otherwise - float/double is enough.



回答6:

The worst accuracy of storing as double is about 3 nm.

If you'd like to calculate it in Java:

Math.ulp((double) 180) * 60 * 1852

3.1582203519064933E-9

As a bonus; the worst accuracy you get from storing in floats is 1.7 meters.