Kotlin: Interface … does not have constructors

2019-01-22 16:29发布

问题:

I am converting some of my Java code to Kotlin and I do not quite understand how to instantiate interfaces that are defined in Kotlin code. As an example, I have an interface (defined in Java code):

public interface MyInterface {
    void onLocationMeasured(Location location);
}

And then further in my Kotlin code I instantiate this interface:

val myObj = new MyInterface { Log.d("...", "...") }

and it works fine. However, when I convert MyInterface to Kotlin:

interface MyInterface {
    fun onLocationMeasured(location: Location)
}

I get an error message: Interface MyListener does not have constructors when I try to instantiate it - though it seems to me that nothing has changed except syntax. Do I misunderstand how interfaces work in Kotlin?

回答1:

Your Java code relies on SAM conversion - an automatic conversion of a lambda into an interface with a single abstract method. SAM conversion is currently not supported for interfaces defined in Kotlin. Instead, you need to define an anonymous object implementing the interface:

val obj = object : MyInterface {
    override fun onLocationMeasured(location: Location) { ... }
}


回答2:

The best solution is to use a typealias in-place of your Java interface

typealias MyInterface = (Location) -> Unit

fun addLocationHandler(myInterface:MyInterface) {

}

Register it like this:

val myObject = { location -> ...}
addLocationHandler(myObject)

or even cleaner

addLocationHandler { location -> ...}

Invoke it like this:

myInterface.invoke(location)

The 3 current options seem to be:

  • typealias (messy when called from java)
  • kotlin interface (messy when called from kotlin; you need to create an object) This is a big step back IMO.
  • java interface (less messy when called from kotlin; lambda needs interface name prepended so you don't need an object; also can't use lambda outside of function parenthesis convention)

When converting our libraries to Kotlin, we actually left all the interfaces in Java code, as it was cleaner to call Java from Kotlin than Kotlin from Kotlin.



回答3:

if you have Java class like this :

recyclerView.addOnItemTouchListener(new RecyclerTouchListener(getActivity(), recyclerView, new RecyclerTouchListener.ClickListener()
        {
              //Your Code
        }));

you shoud convert this code from Java to Kotlin like this :

override fun showJozList (list : List<ResponseGetJuzList.Parameter4>) {
        adapter.addData(list)
        jozlist_recycler.addOnItemTouchListener(RecyclerTouchListener(
                activity ,
                jozlist_recycler ,
                object : RecyclerTouchListener.ClickListener
                    {
                          //Your Code
                    }))

convert Java Interface :

new RecyclerTouchListener.ClickListener()

to Kotlin Interface Style:

object : RecyclerTouchListener.ClickListener


回答4:

Try to access to your interface like this :

 object : MyInterface {
    override fun onSomething() { ... }
}


标签: java kotlin