For my application I'm using a TableView and using customized UITableViewCells.
I customized my cells via interface builder, not programmatically. Is there a way to also make the background color of my customized cell a gradient in the interface builder?
Thanks.
To draw a gradient, you will have to subclass and override the drawRect programmatically:
- (void)drawRect:(CGRect)rect
{
CGContextRef context = UIGraphicsGetCurrentContext();
CGContextSaveGState(context);
CGColorSpaceRef colorSpace = CGColorSpaceCreateDeviceRGB();
CGGradientRef gradient = CGGradientCreateWithColorComponents
(colorSpace,
(const CGFloat[8]){1.0f, 0.0f, 0.0f, 1.0f, 0.0f, 1.0f, 0.0f, 1.0f},
(const CGFloat[2]){0.0f,1.0f},
2);
CGContextDrawLinearGradient(context,
gradient,
CGPointMake(CGRectGetMidX(self.bounds), CGRectGetMinY(self.bounds)),
CGPointMake(CGRectGetMidX(self.bounds), CGRectGetMaxY(self.bounds)),
0);
CGColorSpaceRelease(colorSpace);
CGContextRestoreGState(context);
}
The easiest way, which keeps your cells in the interface builder, is probably to subclass a UIView to have it draw a gradient in its drawRect and place it in your cell behind the other subviews:
GradientView *gradientView = [[GradientView alloc] init];
gradientView.frame = cell.bounds;
[cell addSubview:gradientView];
[cell sendSubviewToBack:gradientView];
However, the best way to do it is probably not to use the interface builder for this and make a subclass of UITableViewCell. For advanced customization, interface builders tend to only make things more complicated in my experience. That's up to personal preference though.
This works for Swift 3.0: (Updated for Swift 4.0)
@IBDesignable
final class GradientView: UIView {
@IBInspectable var startColor: UIColor = UIColor.clear
@IBInspectable var endColor: UIColor = UIColor.clear
override func draw(_ rect: CGRect) {
let gradient: CAGradientLayer = CAGradientLayer()
gradient.frame = CGRect(x: CGFloat(0),
y: CGFloat(0),
width: superview!.frame.size.width,
height: superview!.frame.size.height)
gradient.colors = [startColor.cgColor, endColor.cgColor]
gradient.zPosition = -1
layer.addSublayer(gradient)
}
}
CAGradientLayer *gradient = [CAGradientLayer layer];
gradient.frame = yourView.bounds;
gradient.colors = [NSArray arrayWithObjects:(id)[[UIColor blackColor] CGColor], (id) [[UIColor whiteColor] CGColor], nil];
[yourView.layer insertSublayer:gradient atIndex:0];
Yes this is possible : Make a image in gradient with 1 X Height pix.
Set this to backgroundColor for cell.
cell.backgroundColor = [UIColor colorWithPatternImage:[UIImage imageNamed:@"gradImage.png"]];
**You can set gradient color with code but its time taken process. If you fill better then search for that.
answer by etayluz works fine but I added a couple changes:
- Gradient size defined by own layer bounds, not the superview.
Remove Gradient layer on every draw, so that it does not keep drawing and adding a new layer when redraw is necessary (for instance by calling .setNeedsDisplay()
on rotation).
@IBDesignable final class MFGradientView: UIView {
@IBInspectable var startColor: UIColor = UIColor.clear
@IBInspectable var endColor: UIColor = UIColor.clear
override func draw(_ rect: CGRect) {
layer.sublayers?.first?.removeFromSuperlayer()
let gradient: CAGradientLayer = CAGradientLayer()
gradient.frame = CGRect(origin: CGPoint.zero, size: self.bounds.size)
gradient.colors = [startColor.cgColor, endColor.cgColor]
layer.insertSublayer(gradient, at: 0)
}
}
Based on etayluz answer I changed the code a little bit by taking the layerClass property of a UIView into account, so you do not need a separate layer as a sublayer.
I think it is much cleaner and it also works with live updates in the Interface Builder.
@IBDesignable final class GradientView: UIView {
@IBInspectable var startColor: UIColor = UIColor.red
@IBInspectable var endColor: UIColor = UIColor.blue
override class var layerClass: AnyClass {
get {
return CAGradientLayer.self
}
}
override init(frame: CGRect) {
super.init(frame: frame)
setupGradient()
}
required init?(coder aDecoder: NSCoder) {
super.init(coder: aDecoder)
setupGradient()
}
private func setupGradient() {
let gradient = self.layer as! CAGradientLayer
gradient.colors = [startColor.cgColor, endColor.cgColor]
}
}
Create a simple view class with @IBInspectable properties.
- Create gradient layer once
- Reuse gradient layer each layout subviews
...
//
// GradientView.swift
//
// Created by Maksim Vialykh on 23.08.2018.
// Copyright © 2018 Vialyx. All rights reserved.
//
import UIKit
class GradientView: UIView {
@IBInspectable
var startColor: UIColor = .white
@IBInspectable
var endColor: UIColor = .black
private let gradientLayerName = "Gradient"
override func layoutSubviews() {
super.layoutSubviews()
setupGradient()
}
private func setupGradient() {
var gradient: CAGradientLayer? = layer.sublayers?.first { $0.name == gradientLayerName } as? CAGradientLayer
if gradient == nil {
gradient = CAGradientLayer()
gradient?.name = gradientLayerName
layer.addSublayer(gradient!)
}
gradient?.frame = bounds
gradient?.colors = [startColor.cgColor, endColor.cgColor]
gradient?.zPosition = -1
}
}
I don't know if there is a gradient option, but you could add an UIImageView to the custom cell and add an image with a gradient.
No, you can't. You could use UISegmentedControl with one segment in older sdk and xCode versions:
http://chris-software.com/index.php/2009/05/13/creating-a-nice-glass-buttons/
But now you can't make less than two segments in one UISegmentedControl. And even this way you couldn't change the default colors of the buttons without coding.