Python input does not compare properly [closed]

问题:

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Closed 6 years ago.

I did this on test today and came back to test it. I know better ways to do this but why is this not working?

def f():
    e=raw_input('enter number')
    if e in range (12):
        print 'co'
    if e in range (12,20):
        print 'co2'
    if e in range (-10,0,1):
        print 'co3'

f()

回答1:

e is a string and you compare it to an int

do

def f():
    e=int(raw_input('enter number'))
    if e in range (12):
        print 'co'
    elif e in range (12,20):
        print 'co2'
    elif e in range (-10,0,1):
        print 'co3'

f()

instead

回答2:

e=raw_input('enter number') should be e=int(raw_input('enter number')) Unlike input(), raw_input() simply returns the input as a string, irrespective of what the input is. Since range(12) consists of the integers 0-11 inclusive but e is not an integer, e will never be in range(12). Thus e needs to be converted into an integer. Fortunately, there is a built-in function for that: int().