IP Address to Integer - C

I previously posted how to implement a function that will convert an integer to an IP address string. So how would we go vice-versa, that is, given a string (154.111.23.23) that is an address, how can we get that integer back, using no inet functions.

回答1:

scanf the string into four bytes and add/shift them into a 32 bit integer.

回答2:

Posix.1-2001 provides inet_pton() for this task. There's a couple of ms-windows versions of this too.

回答3:

//No checking of the input    
unsigned int c1,c2,c3,c4;
scanf("%d.%d.%d.%d",&c1,&c2,&c3,&c4);
unsigned long ip = (unsigned long)c4+c3*256+c2*256*256+c1*256*256*256;
printf("The unsigned long integer is %lu\n",ip);

EDIT: For those how are interested on the code produced, GCC is smart enough to replace my multiplication of 256 with shifts left. (In my program I've also called exit):

0x80483d4   <main>:     lea    0x4(%esp),%ecx
0x80483d8   <main+4>:       and    $0xfffffff0,%esp
0x80483db   <main+7>:       pushl  -0x4(%ecx)
0x80483de   <main+10>:      push   %ebp
0x80483df   <main+11>:      mov    %esp,%ebp
0x80483e1   <main+13>:      push   %ecx
0x80483e2   <main+14>:      sub    $0x34,%esp
0x80483e5   <main+17>:      lea    -0x14(%ebp),%eax
0x80483e8   <main+20>:      mov    %eax,0x10(%esp)
0x80483ec   <main+24>:      lea    -0x10(%ebp),%eax
0x80483ef   <main+27>:      mov    %eax,0xc(%esp)
0x80483f3   <main+31>:      lea    -0xc(%ebp),%eax
0x80483f6   <main+34>:      mov    %eax,0x8(%esp)
0x80483fa   <main+38>:      lea    -0x8(%ebp),%eax
0x80483fd   <main+41>:      mov    %eax,0x4(%esp)
0x8048401   <main+45>:      movl   $0x8048520,(%esp)
0x8048408   <main+52>:      call   0x8048320 <scanf@plt>
0x804840d   <main+57>:      mov    -0x8(%ebp),%eax
0x8048410   <main+60>:      mov    %eax,%edx
0x8048412   <main+62>:      shl    $0x8,%edx
    0x8048415   <main+65>:      mov    -0xc(%ebp),%eax
0x8048418   <main+68>:      lea    (%edx,%eax,1),%eax
0x804841b   <main+71>:      mov    %eax,%edx
0x804841d   <main+73>:      shl    $0x8,%edx
0x8048420   <main+76>:      mov    -0x10(%ebp),%eax
0x8048423   <main+79>:      lea    (%edx,%eax,1),%eax
0x8048426   <main+82>:      mov    %eax,%edx
0x8048428   <main+84>:      shl    $0x8,%edx
0x804842b   <main+87>:      mov    -0x14(%ebp),%eax
0x804842e   <main+90>:      lea    (%edx,%eax,1),%eax
0x8048431   <main+93>:      mov    %eax,-0x18(%ebp)
0x8048434   <main+96>:      mov    -0x18(%ebp),%eax
0x8048437   <main+99>:      mov    %eax,0x4(%esp)
0x804843b   <main+103>:     movl   $0x804852c,(%esp)
0x8048442   <main+110>:     call   0x8048330 <printf@plt>
0x8048447   <main+115>:     movl   $0x0,(%esp)
0x804844e   <main+122>:     call   0x8048340 <exit@plt>

回答4:

uint32_t getDecimalValueOfIPV4_String(const char* ipAddress)
{
    uint8_t ipbytes[4]={};
    int i =0;
    int8_t j=3;
    while (ipAddress+i && i<strlen(ipAddress))
    {
       char digit = ipAddress[i];
       if (isdigit(digit) == 0 && digit!='.'){
           return 0;
       }
        j=digit=='.'?j-1:j;
       ipbytes[j]= ipbytes[j]*10 + atoi(&digit);

        i++;
    }

    uint32_t a = ipbytes[0];
    uint32_t b =  ( uint32_t)ipbytes[1] << 8;
    uint32_t c =  ( uint32_t)ipbytes[2] << 16;
    uint32_t d =  ( uint32_t)ipbytes[3] << 24;
    return a+b+c+d;
}