Why do I get numbers as output result when using wchar_t?
#include <iostream>
using namespace std;
int main()
{
wchar_t q;
q = 'A';
cout << q;
q = 'B';
cout << q;
q = 'C';
cout << q;
return 0;
}
Why do I get numbers as output result when using wchar_t?
#include <iostream>
using namespace std;
int main()
{
wchar_t q;
q = 'A';
cout << q;
q = 'B';
cout << q;
q = 'C';
cout << q;
return 0;
}
The displayed 'numbers' are the value of the character. That's the reason you get 'numbers'. If you want to display the characters you can use wcout
std::cout
is a basic_iostream<char>
. There is no operator<<
overload for wchar_t
for basic_iostream<char>
. When you output wchar_t
objects they must be converted to some type for which there is an operator<<
overload. The selected conversion is to an integral type other than char
and so the integral value is shown instead of the represented character.