I m trying to find how to make a division in ARM since there is no DIV command. If that can be done by multiplication of a float number [/9 = *0.09], by subtraction or by the use of a library. Any way would do.
Currently I am doing division using subtraction using a loop like this but I loose the decimals:
MOV R0,#70 ;Fahrenheit Temperature
SUB R1,R0,#32 ; Subtracting 32
MOV R4,#0 ;Counter
LOOP
ADD R4,R4,#1; Counter+1 ->Is the answer of the division without decimals
SUB R1,#9
CMP R1,#0
BPL LOOP
MOV R1,R4
So basically what I am doing is that I have temperature 70, I subtract 32 and I get 38. Then in the loop I take 9 each time till the reminder is smaller than 9. The answer using normal division is 4.22222. Here I get 5. So my result is not as accurate.
If you just want to divide an integer value in r0 by 9 you can approximate that with:
ldr r3,=0x1C71C71D # 1C71C71D == (2^32 / 9) + 1
umull r9,r3,r0,r3
r3 now contains the integer part of the quotient, and r9 contains the fractional part scaled by 2^32. To get the remainder you'd just multiply the integer part of the quotient by 9 and subtract the result from the original value.
Michael's answer is right if you divide the number by a constant and you need an integer result. You won't get the fraction part like you want.
If you need a floating-point result you'll need a floating-point division function, which is not easy to implement in software and asm on architectures without FPU. ARMv7 and above have FPU/SIMD by default, some ARMv6 and below also have FPU so you can divide it directly in hardware
A fixed-point solution may be easier, just divide the number like normal integer division but remember to adjust the result after calculation. Of course fixed-point number won't have large dynamic range like floating-point but in your case I think the range is enough. You can also multiply the remainder by 10n, with n is the number of digits after decimal sign you need, then divide it with the above divisor again to get the fractional part
For example to get the result of 22/9 with 3 digits of precision do as follow:
22/9 = 2 remains 4
4*10^3 = 4000
4000/9 = 444
→ 22/9 = 2.444
To get more precision, just multiply the remainder with a larger power of 10
