INT32U and INT8U in Objective C

问题:

I am getting errors withis below declaration.when declared INT32U i'm getting errors.

Though INT32U and int are 4 bytes.How will i declare the equivalent of INT8U.I cant use int here as its INT8U is 2 bytes.

INT32U_C Uucode(INT8U_C* pDst,const INT8U_C* pSrc,INT32U_C nSrcLen);

Error:Expected '=',','";" 'asm' or 'attribute' before Uucode.

回答1:

stdint.h has specific-size integer definitions, including uint32_t and uint8_t.