Java: startingPath as “public static final” except

2020-05-06 13:35发布

问题:

[Updated, sorry about the change but now to the real problem] I cannot include try-catch-loop there for the exception from the method getCanonicalPath(). I tried to solve the problem earlier with method and then declaring the value there. The problem is that it is Final, I am unable to change it. So how to have startingPath as "public static final".

$ cat StartingPath.java 
import java.util.*;
import java.io.*;

public class StartingPath {
 public static final String startingPath = (new File(".")).getCanonicalPath();

 public static void main(String[] args){
  System.out.println(startingPath);
 }
}
$ javac StartingPath.java 
StartingPath.java:5: unreported exception java.io.IOException; must be caught or declared to be thrown
 public static final String startingPath = (new File(".")).getCanonicalPath();
                                                                           ^
1 error

回答1:

The name is fine; you forgot to declare the type.

public static final String startingPath;
//                  ^^^^^^

Fixing that, you of course realize the harder problem of how to deal with the possible IOException and startingPath being final. One way is to use a static initializer:

JLS 8.7 Static Initializers

Any static initializers declared in a class are executed when the class is initialized and, together with any field initializers for class variables, may be used to initialize the class variables of the class.

 public static final String startingPath;
 static {
    String path = null;
    try {
      path = new File(".").getCanonicalPath();
    } catch (IOException e) {
      // do whatever you have to do
    }
    startingPath = path;
 }

Another way is to use a static method (see Kevin Brock's answer). That approach actually results in better readability, and is the recommended approach by Josh Bloch in Effective Java.


See also

  • How to handle a static final field initializer that throws checked exception?
  • In what order do static initializer blocks in Java run?


回答2:

You can provide a static method to initialize your static variable:

public static final String startingPath = initPath();

private static String initPath() {
    try {
        return new File(".").getCanonicalPath();
    } catch (IOException e) {
        throw new RuntimeException("Got I/O exception during initialization", e);
    }
}

Or you can initialize your variable in a static block:

public static final String startingPath;

static {
    try {
        startingPath = new File(".").getCanonicalPath();
    } catch (IOException e) {
        throw new RuntimeException("Got I/O exception during initialization", e);
    }
}

EDIT: In this case your variable is static so there is no way to declare the exception thrown. Just for reference, if the variable is non-static you could do this by declaring the thrown exception in the constructor, like so:

public class PathHandler {

    private final String thePath = new File(".").getCanonicalPath();

    public PathHandler() throws IOException {
        // other initialization
    }


回答3:

Just initialize it in the static block(the variable is final). You can't catch exceptions on declaring a variable.



回答4:

You are missing the type of your variable, it should be

public static void String startingPath ...


回答5:

 public static final String startingPath = (new File(".")).getCanonicalPath();

You are missing the type of variable startingPath