Find out who is logged in on linux using python [c

问题:

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Closed 7 years ago.

I have 8 servers that I would like to monitor. All servers have a tornado python server installed. One of the servers is a monitor that polls other servers and alerts me by SMS if there is a problem.

One of the alerts is when a user logs into one of the servers.

How can I use Python to detect who is logged in on my Ubuntu server? I need to return logged in users to the main monitor. I hope this makes things clear..

回答1:

The best thing I found online is psutil. See the psutil documentation

First install psutil :

pip install psutil

After that everything is easy as an example run python console from terminal:

import psutil 

psutil.users()

Output:

[user(name='root', terminal='pts/0', host='your-local-host-from-isp.net',
started=1358152704.0)]

回答2:

Use the subprocess module, and run the command who.

In [5]: import subprocess

In [6]: subprocess.check_output("who")
Out[6]: 'monty    pts/0        2013-01-14 16:21 (:0.0)\n'

You can fetch the number of current logins using : who | wc -l:

In [42]: !who
monty    pts/2        2013-01-14 19:09 (:0.0)
monty    pts/0        2013-01-14 19:07 (:0.0)

In [43]: p=Popen(["who"],stdout=PIPE)

In [44]: Popen(["wc","-l"],stdin=p.stdout).communicate()[0]
2

Names of the users:

In [54]: users=check_output("who")

In [55]: set([x.split()[0] for x in users.splitlines()])
Out[55]: set(['monty'])

回答3:

from subprocess import Popen, PIPE, STDOUT

who = Popen(['who'],stdin=PIPE, stdout=PIPE, stderr=STDOUT)
print who.stdout.read()

# Output 
>>> sudo_O  :0           2013-01-14 11:48 (:0)
>>> sudo_O  pts/0        2013-01-14 11:48 (:0)
>>> sudo_O  pts/1        2013-01-14 12:41 (:0)
>>> sudo_O  pts/2        2013-01-14 12:42 (:0)

回答4:

And if you dont want to install 3-rd party software. You can always run unix who utility

import os
os.popen('who').read()

回答5:

In [1]: import subprocess
In [2]: print subprocess.check_output("who").split()[0]
Out[3]: 'rikatee'