What is the simplest RGB image format?

问题:

I am working in C on a physics experiment, Young's interference experiment and i made a program who prints to file a huge bunch of pixels :

for (i=0; i < width*width; i++)
{
    fwrite(hue(raster_matrix[i]), 1, 3, file);
}

Where hue, when given a value [0..255], gives back a char * with 3 bytes, R,G,B.

I would like to put a minimal header in my image file in order to make this raw file a valid image file.

More concise : Switching from :

offset
0000 : height * width : data } my data, 24bit RGB pixels

to

offset
0000 : dword : magic        \
     : /* ?? */              \
0012 : dword : height         } Header <--> common image file
0016 : dword : width         /
     : /* ?? */             /
0040 : height * width : data  } my data, 24bit RGB pixels

Thank you.

回答1:

You probably want to use the PPM format which is what you're looking for: a minimal header followed by raw RGB.

回答2:

The recently created farbfeld format is quite minimal, though there is not much software supporting it (at least so far).

Bytes                  │ Description
8                      │ "farbfeld" magic value
4                      │ 32-Bit BE unsigned integer (width)
4                      │ 32-Bit BE unsigned integer (height)
(2+2+2+2)*width*height │ 4*16-Bit BE unsigned integers [RGBA] / pixel, row-major

回答3:

TARGA (file name extension .tga) may be the simplest widely supported binary image file format if you don't use compression and don't use any of its extensions. It's even simpler than Windows .bmp files and is supported by ImageMagick and many paint programs. It has been my go-to format when I just need to output some pixels from a throwaway program.

Here's a minimal C program to generate an image to standard output:

#include <stdio.h>
#include <string.h>

enum { width = 550, height = 400 };

int main(void) {
  static unsigned char pixels[width * height * 3];
  static unsigned char tga[18];
  unsigned char *p;
  size_t x, y;

  p = pixels;
  for (y = 0; y < height; y++) {
    for (x = 0; x < width; x++) {
      *p++ = 255 * ((float)y / height);
      *p++ = 255 * ((float)x / width);
      *p++ = 255 * ((float)y / height);
    }
  }
  tga[2] = 2;
  tga[12] = 255 & width;
  tga[13] = 255 & (width >> 8);
  tga[14] = 255 & height;
  tga[15] = 255 & (height >> 8);
  tga[16] = 24;
  tga[17] = 32;
  return !((1 == fwrite(tga, sizeof(tga), 1, stdout)) &&
           (1 == fwrite(pixels, sizeof(pixels), 1, stdout)));
}

回答4:

Here's a minimal example that writes your image file with a minimal PPM header:

#include <stdio.h>
#include <stdlib.h>

#include <math.h> // compile with gcc -lm
#define WAVE(x,y) sin(sqrt( (x)*(x)+(y)*(y) ) / 3.0)

int main(){
    /* Setup code */
    #define width 256
    unsigned char raster_matrix[width*width];
    unsigned char a[3];
    #define hue(c) (a[0] = c, a[1] = 128, a[2] = 255-c, a)

    int x, y, i = 0;
    for (y = 0; y < width; y++) for (x = 0; x < width; x++)
        raster_matrix[i++] = 128 + 64*(WAVE(x,y) + WAVE(x,width-y));


    /* Open PPM File */
    FILE *file = fopen("young.ppm", "wb"); if (!file) return -1;

    /* Write PPM Header */
    fprintf(file, "P6 %d %d %d\n", width, width, 255); /* width, height, maxval */

    /* Write Image Data */
    for (i=0; i < width*width; i++)
        fwrite(hue(raster_matrix[i]), 1, 3, file);

    /* Close PPM File */
    fclose(file);

    /* All done */
    return 0;
}

I wrote the header code based on the specs at http://netpbm.sourceforge.net/doc/ppm.html.

I hacked in some setup code so I could incorporate the for loop given in the question. :)