php check if value exsist in array, in another arr

问题:

I have a array dataImages which holds the arrays of image informations and looks like this

Array ( 
    [0] => Array ( 
        [id] => 104 
        [name] => sample-large-Test-1-a52d268be9ad9c.png 
        [user] => 31 
        [main_image] => 1 
    ) 
    [1] => Array ( 
        [id] => 105 
        [name] => sample-large-Test-1-a52d268bee6ba5.jpg 
        [user] => 31 
        [main_image] => 0 
    ) 
    [2] => Array ( 
        [id] => 106 
        [name] => sample-large-Test-1-a52d268bf4c457.jpg 
        [user] => 31 
        [main_image] => 0 
    ) 
) 

How can i check if in array dataImages is an image with main_image === 1 and how can i show data for that image?

回答1:

You can do this in loop also:

foreach ($dataImages as $image){
    if ($image['main_image']) print_r($image)
}

回答2:

There might be a better depending on what you want to do exactly (e.g. just loop), but one option is array_filter in which case you can do

function hasMain($var){
 return $var["main_image"];
}

print_r(array_filter($theArray, "hasMain"));

回答3:

function getMainImage($images) {
    if(!is_array($images))
        return null;

    foreach($images as $image) {
        if(isset($image['main_image']) && $image['main_image'] == 1)
            return $image;
    }

    return null;
}

$mainImage = getMainImage($myImages);

Something like this should do the trick.

You can check if a variable contains an array by using is_array. http://nl1.php.net/manual/en/function.is-array.php

回答4:

$main_image = FALSE;
$img = '';

foreach($images as $image) {
  if ( $image['main_image'] == 1 ){
    $main_image = TRUE;
    $img = $image['name'];
    break;
  }
}