可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试):
问题:
It seems, most code for rendering view into string doesn't work in MVC 5.
I have latest MVC 5.1.2 templates and I am trying to render view into string.
public static String RenderViewToString(ControllerContext context, String viewPath, object model = null)
{
context.Controller.ViewData.Model = model;
using (var sw = new StringWriter())
{
var viewResult = ViewEngines.Engines.FindView(context, viewPath, null);
var viewContext = new ViewContext(context, viewResult.View, context.Controller.ViewData, context.Controller.TempData, sw);
viewResult.View.Render(viewContext, sw);
viewResult.ViewEngine.ReleaseView(context, viewResult.View);
return sw.GetStringBuilder().ToString();
}
}
Well, it's working but its output contains lots of $ marks instead tags. I read something about it was fixed in RC version, but that's old news.
Problem looks like this
<$A$><h1></h1>
<table</$A$><$B$> class=""</$B$><$C$>> <tbody</$C$><$D$></$D$><$E$>></tbody>
</table></$E$>
I would like to ask, how do you render views into string in latest MVC 5 template ?
Thanks.
回答1:
Ok, seems I found a solution. Author of the idea is Yakir Manor.
class FakeController : ControllerBase
{
protected override void ExecuteCore() { }
public static string RenderViewToString(string controllerName, string viewName, object viewData)
{
using (var writer = new StringWriter())
{
var routeData = new RouteData();
routeData.Values.Add("controller", controllerName);
var fakeControllerContext = new ControllerContext(new HttpContextWrapper(new HttpContext(new HttpRequest(null, "http://google.com", null), new HttpResponse(null))), routeData, new FakeController());
var razorViewEngine = new RazorViewEngine();
var razorViewResult = razorViewEngine.FindView(fakeControllerContext, viewName, "", false);
var viewContext = new ViewContext(fakeControllerContext, razorViewResult.View, new ViewDataDictionary(viewData), new TempDataDictionary(), writer);
razorViewResult.View.Render(viewContext, writer);
return writer.ToString();
}
}
}
It's a trick with fake context and response.
Example:
String renderedHTML = RenderViewToString("Email", "MyHTMLView", myModel );
My file MyHTMLView.cstml is stored in Views/Email/MyHTMLView.cshtml. Email is a fake controller name.
回答2:
following is the solution that works with session and areas on MVC5.
public class FakeController : ControllerBase
{
protected override void ExecuteCore() { }
public static string RenderViewToString(string controllerName, string viewName,string areaName, object viewData,RequestContext rctx)
{
try
{
using (var writer = new StringWriter())
{
var routeData = new RouteData();
routeData.Values.Add("controller", controllerName);
routeData.Values.Add("Area", areaName);
routeData.DataTokens["area"] = areaName;
var fakeControllerContext = new ControllerContext(rctx, new FakeController());
//new ControllerContext(new HttpContextWrapper(new HttpContext(new HttpRequest(null, "http://google.com", null), new HttpResponse(null))), routeData, new FakeController());
fakeControllerContext.RouteData = routeData;
var razorViewEngine = new RazorViewEngine();
var razorViewResult = razorViewEngine.FindView(fakeControllerContext, viewName, "", false);
var viewContext = new ViewContext(fakeControllerContext, razorViewResult.View, new ViewDataDictionary(viewData), new TempDataDictionary(), writer);
razorViewResult.View.Render(viewContext, writer);
return writer.GetStringBuilder().ToString();
//use example
//String renderedHTML = RenderViewToString("Email", "MyHTMLView", myModel );
//where file MyHTMLView.cstml is stored in Views/Email/MyHTMLView.cshtml. Email is a fake controller name.
}
}
catch (Exception ex)
{
//do your exception handling here
}
}
}
here is how you call this from another controller
var modal = getModal(params);
return FakeController.RenderViewToString(controllerName, viewName, areaName, modal, this.Request.RequestContext);
using requestcontext we can easily pass current session in fakecontroller and render razor string.
回答3:
I had an immediate need to return 6 partial views as strings in a JSON object. Instead of creating a static method, and passing all the unneeded parameters, I decided to add protected methods to our ControllerBase class that derives from Controller, and is used as the base class for all of our controllers.
Here is a fully functional ControllerBase class that provides this functionality, and works very similar to the PartialView() and View() methods that are in the Controller class. It includes the additions from @Alok.
public abstract class ControllerBase : Controller
{
#region PartialViewToString
protected string PartialViewToString(string partialViewName, object model = null)
{
ControllerContext controllerContext = new ControllerContext(Request.RequestContext, this);
return ViewToString(
controllerContext,
ViewEngines.Engines.FindPartialView(controllerContext, partialViewName) ?? throw new FileNotFoundException("Partial view cannot be found."),
model
);
}
#endregion
#region ViewToString
protected string ViewToString(string viewName, object model = null)
{
ControllerContext controllerContext = new ControllerContext(Request.RequestContext, this);
return ViewToString(
controllerContext,
ViewEngines.Engines.FindView(controllerContext, viewName, null) ?? throw new FileNotFoundException("View cannot be found."),
model
);
}
protected string ViewToString(string viewName, string controllerName, string areaName, object model = null)
{
RouteData routeData = new RouteData();
routeData.Values.Add("controller", controllerName);
if (areaName != null)
{
routeData.Values.Add("Area", areaName);
routeData.DataTokens["area"] = areaName;
}
ControllerContext controllerContext = new ControllerContext(HttpContext, routeData, this);
return ViewToString(
controllerContext,
ViewEngines.Engines.FindView(controllerContext, viewName, null) ?? throw new FileNotFoundException("View cannot be found."),
model
);
}
#endregion
#region Private Methods
private string ViewToString(ControllerContext controllerContext, ViewEngineResult viewEngineResult, object model)
{
using (StringWriter writer = new StringWriter())
{
ViewContext viewContext = new ViewContext(
ControllerContext,
viewEngineResult.View,
new ViewDataDictionary(model),
new TempDataDictionary(),
writer
);
viewEngineResult.View.Render(viewContext, writer);
return writer.ToString();
}
}
#endregion
}
回答4:
@wh1sp3r answer works but for partial views I had to do the following minor changes:
string html = FakeController.RenderViewToString("**Controllername**", "~/views/**Controllername**/_AsdfPartialPage.cshtml", fem);
public static string RenderViewToString(string controllerName, string viewName, object viewData)
{
using (var writer = new StringWriter())
{
var routeData = new RouteData();
routeData.Values.Add("controller", controllerName);
var fakeControllerContext = new ControllerContext(new HttpContextWrapper(new HttpContext(new HttpRequest(null, "http://localhost", null), new HttpResponse(null))), routeData, new FakeController());
var razorViewEngine = new RazorViewEngine();
//var razorViewResult = razorViewEngine.FindView(fakeControllerContext, viewName, "", false);
var razorViewResult = razorViewEngine.FindPartialView(fakeControllerContext, viewName, false);
var viewContext = new ViewContext(fakeControllerContext, razorViewResult.View, new ViewDataDictionary(viewData), new TempDataDictionary(), writer);
razorViewResult.View.Render(viewContext, writer);
return writer.ToString();
}
}