Changing the value of range during iteration in Py

2020-04-20 22:17发布

问题:

>>> k = 8
>>> for i in range(k):
        print i
        k -= 3
        print k

Above the is the code which prints numbers from 0-7 if I use just print i in the for loop.

I want to understand the above code how it is working, and is there any way we can update the value of variable used in range(variable) so it iterates differently.

Also why it always iterates up to the initial k value, why the value doesn't updated.

I know it's a silly question, but all ideas and comments are welcome.

回答1:

You can't change the range after it's been generated. In Python 2, range(k) will make a list of integers from 0 to k, like this: [0, 1, 2, 3, 4, 5, 6, 7]. Changing k after the list has been made will do nothing.

If you want to change the number to iterate to, you could use a while loop, like this:

k = 8
i = 0
while i < k:
    print i
    k -= 3
    i += 1


回答2:

The expression range(k) is evaluated just once, not on every iteration. You can't set k and expect the range(k) result to change, no. From the for statement documentation:

The expression list is evaluated once; it should yield an iterable object.

You can use a while loop instead:

i = 0
k = 8
while i < k:
    print i
    i += 1
    k -= 3

A while loop does re-evaluate the test each iteration. Referencing the while statement documentation:

This repeatedly tests the expression and, if it is true, executes the first suite



回答3:

If you do want to change k and affect the loop you need to make sure you are iterating over mutable object. For example:

k = list(range(8))
for i in k:
        print(i)
        k.pop()
        k.pop()
        k.pop()
        print(k)

Or alternatively:

k = list(range(8))
for i in k:
        print(i)
        k[:] = k[:-3]
        print(k)

Both will result with

0
[0, 1, 2, 3, 4]
1
[0, 1]